Finding absolute value or modulus of a complex number :
The length of the line segment, that is OP, is called the modulus of the complex number
To find the modulus of a complex number a + ib, we have to use the formula √(a2 + b2).
Find the absolute value of the complex numbers given below :
Problem 1 :
4 + 3i
Solution :
Comparing the given complex number with the general form of a complex number a + ib, we get
a = 4 and b = 3
= √(42 + 32)
= √(16 + 9)
= √25
= 5
So, the absolute value of the given complex number is 5.
Problem 2 :
-√15 + i √15
Solution :
Comparing the given complex number with the general form of a complex number a + ib, we get
a = -√15 and b = √15
= √(-√15)2 + (√15)2
= √15 + 15
= √30
So, the absolute value of the complex number is √30.
Problem 3 :
Solution :
Since the given is in the form of polar form, we have to convert it into rectangular form and then find the absolute value.
Finding absolute value :
a = 0 and b = -1
= 3√02 + (-1)2
= 3√1
= 3
So, the absolute value of the given complex number is 3.
Problem 4 :
Solution :
Finding absolute value :
a = 0 and b = 1
= √21 (√02 + 12)
= √21 (1)
= √21
So, the absolute value of the given complex number is √21.
Problem 5 :
(-2√3 - 2i)
Solution :
Let z = (-2√3 - 2i)
Comparing the given complex number with the general form of a complex number a + ib, we get
a = -2√3 and b = -2
= √(-2√3)2 + (-2)2
Distributing square separately, we get
= √(4(3) + 4)
= √(12 + 4)
= √16
= 4
So, the absolute value of the complex number is 4.
Problem 6 :
Solution :
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May 21, 24 08:51 AM
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