Problem 21 :
Jeff recorded the average temperatures for six months. He will display the temperatures on a number line
On the number line, which month’s temperature will be between February’s and March’s temperatures?
A) December B) January C) April D) May
Solution :
Temperature is February = -15
Temperature is March = 20
Difference between two temperatures = 20 - (-15)
= 20 + 15
= 35
Problem 22 :
A trapezoid in a coordinate plane has vertices
(-2, 5) (-3, -2) (2, -2) (1, 5)
What is the height of the trapezoid?
A) 3 units B) 5 units C) 7 units D) 9 units
Solution :
So, the answer is 7 units.
Problem 23 :
Which can be represented by the expression 17 – 2x?
A) 17 less than twice a number x
B) the difference between 17 and twice a number x
C) a number x squared, subtracted from 17
D) 17 less than a number x squared
Solution :
17 – 2x
We have negative sign, so we use the word difference.
2x = twice the number
So, difference between 17 and twice a number, option B is correct.
Problem 24 :
Which expression is equivalent to 5y + 2y + 6x + 2y – x?
A) 5x + 6y B) 5x + 7y C) 5x + 9y D) 7x + 7y
Solution :
5y + 2y + 6x + 2y – x
Combining like terms, we get
= 6x - x + 2y + 2y + 5y
= 5x + 9y
So, option C is correct.
Problem 25 :
Diana can use the equation y = 7x to calculate her pay, where y represents the amount of pay, and x represents the number of hours worked. How many hours did Diana work if she was paid $45.50?
A) 5.5 hours B) 6 hours C) 6.5 hours D) 7 hours
Solution :
y = 7x
y = amount of pay
x = number of hours worked
Amount of pay = 45.50
7x = 45.50
x = 45.50/7
x = 6.5
So, option C 6.5 hours is correct.
Problem 26 :
If y – 18 = 14, what is the value of 3(y + 5)?
A) 27 B) 32 C) 96 D) 111
Solution :
y – 18 = 14
y = 14 + 18 ==> 32
Applying the value of y, in 3(y + 5).
= 3(32 + 5)
= 3(37)
= 111
So, the answer is option D, 111.
Problem 27 :
Karen recorded her walking pace in the table below. What equation best represents this relationship?
A) h = m + 10 B) h = 3.5m C) m = h + 10 D) m = 3.5h
Solution :
h - independent variable
m - dependent variable
Rate of change :
(2.5, 8.75) and (4, 14)
Rate of change = (14 - 8.75) / (4 - 2.5)
= 5.25 / 1.5
= 3.5
Equation representing the given table :
m = 3.5h
So, option D is correct.
Problem 28 :
The shaded area indicates the parking lot at a shopping center.
What is the total area of the parking lot?
A) 72 units^{2} B) 86 units^{2} C) 91 units^{2} D) 120 units^{2}
Solution :
We decompose the given shaded region into two trapezium.
Area of trapezium = (1/2) h (a + b)
Area of A1 : h = 2, a = 6, b = 5 = (1/2) x 2 (6 + 5) = 11 square units |
Area of A2 : h = 10, a = 5, b = 10 = (1/2) x 10 (5 + 10) = 75 square units |
= 11 + 75
= 86 square units.
So, option B is correct.
Problem 29 :
The right rectangular prism below is made up of 8 cubes. Each cube has an edge length of 1/2 inch.
What is the volume of this prism?
A) 1 cubic inch B) 2 cubic inches
C) 4 cubic inches D) 8 cubic inches
Solution :
Length of each edge = 1/2 inch
length of prism = 4(1/2) = 2 inches
Width = 1/2 inch
Height = 2(1/2) ==> 1 inch
Volume = length x width x height
= 2 x (1/2) x 1
= 1 cubic inch
So, option A is correct.
Problem 30 :
What is the area of the quadrilateral with vertices at
(-1, 0), (2, 0), (2, 5) and (-1, 5)?
A) 15 square units B) 12 square units
C) 10 square units D) 5 square units
Solution :
The given quadrilateral is a rectangle.
Area of rectangle = length x width
Length = 5, width = 3
= 5 x 3
= 15 square units.
So, option A is correct.
Jun 05, 23 09:20 PM
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