FROM THE POINTS FIND THE EXPONENTIAL FUNCTION

Find a formula for an exponential function passing through the two points.

Problem 1 :

(0, 6), (3, 750)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (0, 6) and (3, 750) for (x, y) in equation

6 = a(b)0

6 = a(1)

a = 6

750 = a(b)3

ab3 = 750 ---> (1)

By applying a = 6 in (1)

6b3 = 750

b3 = 125

b = 5

Exponential equation 

y = a(b)x

y = 6(5)x

Problem 2 :

(0, 3), (2, 75)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (0, 3) and (2, 75) for (x, y) in equation

3 = a(b)0

3 = a(1)

a = 3 

75 = a(b)2

ab2 = 75 ---> (1)

By applying a = 3 in (1).

3b2 = 75

b2 = 25

b = 5

Exponential equation 

y = a(b)x

y = 3(5)x

Problem 3 :

(0, 2000), (2, 20)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (0, 2000) and (2, 20) for (x, y) in equation

2000 = a(b)0

2000 = a(1)

a = 2000 

20 = a(b)2

ab2 = 20 ---> (1)

By applying a = 2000 in (1).

2000b2 = 20

b2=1100b=110

Exponential equation 

y = a(b)x

y=2000110x

Problem 4 :

(0, 9000), (3, 72)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (0, 9000) and (3, 72) for (x, y) in equation

9000 = a(b)0

9000 = a(1)

a = 9000

72 = a(b)3

ab3 = 72 ---> (1)

By applying a = 9000 in (1).

9000b3 = 72

b3=1125b=15

Exponential equation 

y = a(b)x

y=900015x

Problem 5 :

-1,32,(3,24)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (-1, 3/2) and (3, 24) for (x, y) in equation

32=a(b)-132=ab2a=3ba=3b2

24 = a(b)3

ab3 = 24 ---> (1)

By applying a = 3b/2 in (1).

3b2b3=243b42=243b4=48b4=16b=2

If b = 2,

a=3(2)2a=3

Exponential equation 

y = a(b)x

y = 3(2)x

Problem 6 :

-1,25,(1,10)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (-1, 2/5) and (1, 10) for (x, y) in equation

25=a(b)-125=ab5a=2ba=2b5

10 = a(b)1

ab = 10 ---> (1)

By applying a = 2b/5 in (1).

2b5b=102b25=102b2=50b2=25b=5

If b = 5,

a=2(5)5a=2

Exponential equation 

y = a(b)x

y = 2(5)x

Problem 7 :

(-2, 6), (3, 1)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (-2, 6) and (3, 1) for (x, y) in equation

Applying (-2, 6)

6 = a(b)-2

6 = a/b2

6b2 = a

6=ab2a=6b2

1 = ab3

ab3 = 1 ---> (1)

By applying a = 6b2 in (1).

(6b2)b3 = 1

6b5 = 1

b5 = 1/6

b=516
If b=516,
a=65162

Exponential equation 

y = a(b)x

y=65162516x

Problem 8 :

(-3, 4), (3, 2)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (-3, 4) and (3, 2) for (x, y) in equation

4 = a(b)-3

4=ab3a=4b3

2 = ab

ab3 = 2 ---> (1)

By applying a = 4b3 in (1).

(4b3)b3 = 2

4b6 = 2

b6=12b=612
b6=12If b=612,
a=46123

Exponential equation 

y = a(b)x

y=46123612x

Problem 9 :

(3, 1), (5, 4)

Solution:

An exponential function is in the general form

y = a(b)x

Substitute (3, 1) and (5, 4) for (x, y) in equation

1 = a(b)3

ab3 = 1 ---> (1)

4 = a(b)5

ab5 = 4 ---> (2)

Solve for a and b.

14=ab5ab34=b2b=2

If b = 2,

ab3 = 1

a(2)3 = 1

8a = 1

a = 1/8

Exponential equation 

y = a(b)x

y=18(2)x
ab6ab2=59b4=59b=459

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