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Problem 1 :
Find the quadratic polynomial whose zeroes are −2 & 3
Problem 2 :
Find a quadratic polynomial whose zeroes are 2 + √3 and 2 – √3
Problem 3 :
Frame a quadratic polynomial p(x) whose sum of zeroes is -3 and the product of zeroes is -2/3.
Problem 4 :
Find a quadratic polynomial whose sum of zeroes is -12 and product is 14.
Problem 5 :
If the sum of the zeroes of the quadratic polynomial
f(x) = kx2 - 2x + 3 is 3
find k. Solution
Problem 6 :
The sum of the roots of the equation
3x2 + kx + 5 = 0
will be equal to the product of its roots. Solution
Problem 7 :
Find the value of k, given that the product of the roots of the equation
(k + 1)x2 + (4k + 3)x + (k – 1) = 0 is 7/2
Problem 8 :
Form an quadratic polynomial whose roots are 2, and -1/2.
Problem 9 :
What is an equation whose roots are 5+√2 and 5−√2
Problem 10 :
Write down the quadratic equation in general form for which sum and product of the roots are given below.
– 7/2 , 5/2
Problem 11 :
If the product of the zeroes of the polynomial ax2 - 6x - 6 is 4, then the value of a is
a) 2/3 b) 3/2 c) -3/2 d) -2/3
|
1) x2 - x - 6 = 0 2) x2 - 4x + 1 = 0 3) 3x2 +x - 2 = 0 4) x2 + 12 x + 14 = 0 5) k = -6 |
6) k = -5 7) k = -1 8) 2x2 - 4x - 1 = 0 9) x2 - 10x + 23 = 0 10) 2x2 + 7x + 5 = 0 11) a = -3/2 |
Problem 1 :
If the sum of the roots of
4x2 + kx – 7 = 0 is 3,
Find the value of k.
Problem 2 :
Find the value of K if the sum of the roots of equation
(2k – 1)x2 + (4k – 1) x + (K + 3) = 0 is 5/2
Problem 3 :
For what value of K the roots of the following equations are equal :
(i) kx2 + 4x + 3 = 0 (ii) 2x2 + 5x + k = 0
Problem 4 :
If the difference of the roots of 6x2 – 23x + c = 0 is 5/6, find the value of c
Problem 5 :
If the difference of the roots of x2 – 7x + k – 4 = 0 is 5, find the value of k and the roots.
Problem 6 :
Find the value of k given that if one root of
9x2 – 15x + k = 0
exceeds the other by 3. Also find the roots.
Problem 7 :
The product of the roots of the equation
(k + 1)x2 + (4k + 3)x + (k – 1) = 0
is 7/2
Problem 8 :
If one zero of the quadratic polynomial x2 + 3x + k is 2, then the value of k is
a) 10 b) -10 c) 5 d) -5
Problem 9 :
If α, β are the zeroes of polynomial f(x) = x2 - p(x + 1) - c then (α + 1)(β + 1) =
a) c - 1 b) 1 - c c) c d) 1 + c
Problem 10 :
If α, β are the zeroes of the polynomial f(x) = x2 + x + 1, then 1/α + 1/β =
a) 1 b) -1 c) 0 d) none
Problem 11 :
If one of the zeroes of the quadratic polynomial (k - 1) x2 + kx + 1 is -3, then the value of k is
a) 4/3 b) -4/3 c) -2/3 d) 2/3
1) k = -12
2) k = 7/18
3) i) k = 4/3 ii) k = 25/8
4) c = 21
5) k = 10, the roots are 1 and 6.
6) the roots are -2/3 and 7/3.
7) k = -9/5
8) k = -10
9) 1 - c
10) -1
11) k = 4/3
Problem 1 :
Write a quadratic equation in standard form with solutions, x = -3 and x = 4. Use integers for a, b and c.
Problem 2 :
Write a quadratic equation in standard form with solutions, x = 2/3 and x = -5. Use integers for a, b and c.
Problem 3 :
Write an equation of the parabola in intercept form y = a(x - p)(x - q) that has x- intercepts of 9 and 1 and passes through (0, -18).
A) y = -1/2(x - 9)(x - 1) B) y = -1/2(x + 9)(x + 1)
C) y = -2(x - 9)(x - 1) D) y = -2(x + 9)(x + 1)
Problem 4 :
Write an equation of the parabola in intercept form y = a(x - p)(x - q) that has x- intercepts of 12 and -6 and passes through (14, 4).
A) y = 1/10(x - 12)(x + 6) B) y = 1/10(x + 12)(x - 6)
C) y = 10(x - 12)(x + 6) D) y = 10(x + 12)(x - 6)
Problem 5 :
Determine the equation of a quadratic function given zeros x = 4 and point (3, 2).
Problem 6 :
Use the intercepts and a point on the graph below to write the equation of the function.

Problem 7 :
Use the intercepts and a point on the graph below to write the equation of the function.

Problem 8 :
The sum and product of zeroes of p(x) = 63x2 - 7x - 9 are S and P respectively. Find the value of S and P. Find the value of 27S + 14P
a) -1 b) 1 c) 2 d) -2
Problem 9 :
If one zero of the quadratic polynomial 2x2 - 8x - m is 5/2, then find the other zero.
a) 1/2 b) 3/2 c) -3/2 d) -1/2
1) x2 - x - 12 = 0
2) 3x2 + 13x - 10 = 0
3) y = -2(x - 9)(x - 1)
4) y = 1/10(x - 12)(x + 6)
5) y = 2(x - 4)(x - 4)
6) y = (x + 6)(x - 6)
7) y = 3(x + 6)(x - 1)
8) 1
9) the another zeros is 3/2.
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May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM