FIND WHETHER THE LINE JOINING TWO POINTS ARE PARALLEL OR PERPENDICULAR

Determine whether AB is parallel to CD.

Problem 1 :

A(5, 6), B(-1, 3), C(-4, 9), D(-16, 3)

Solution:

Slope of AB:

A(5, 6) ==>(x1, y1), B(-1, 3) ==> (x2, y2)

Slope (m1)=y2-y1x2-x1= (3-6)(-1-5)= -3-6= 12

Slope of CD:

C(-4, 9) ==>(x1, y1), D(-16, 3) ==> (x2, y2)

Slope (m2)=y2-y1x2-x1= (3-9)(-16+4)= -6-12= 12

Slope of AB = Slope of CD

1/2 = 1/2

So, slope of the lines AB and CD are equal.

Hence, the line AB is parallel to CD.

Problem 2 :

A(-3, 6), B(5, 4), C(-14, -10), D(-2, -7)

Solution:

Slope of AB:

A(-3, 6) ==>(x1, y1), B(5, 4) ==> (x2, y2)

Slope (m1)=y2-y1x2-x1= (4-6)(5+3)= -28= -14

Slope of CD:

C(-14, -10) ==>(x1, y1), D(-2, -7) ==> (x2, y2)

Slope (m2)=y2-y1x2-x1= (-7+10)(-2+14)= 312= 14

Slope of AB ≠ Slope of CD

-1/4 ≠ 1/4

So, the lines are neither parallel nor perpendicular.

Problem 3 :

A(6, -3), B(5, 2), C(-4, -4), D(-5, 2)

Solution:

Slope of AB:

A(6, -3) ==>(x1, y1), B(5, 2) ==> (x2, y2)

Slope (m1)=y2-y1x2-x1= (2+3)(5-6)= 5-1=-5

Slope of CD:

C(-4, -4) ==>(x1, y1), D(-5, 2) ==> (x2, y2)

Slope (m2)=y2-y1x2-x1= (2+4)(-5+4)= 6-1=-6

Slope of AB ≠ Slope of CD

-5 ≠ -6

So, the lines are neither parallel nor perpendicular.

Problem 4 :

A(-5, 6), B(-7, 2), C(7, 1), D(4, -5)

Solution:

Slope of AB:

A(-5, 6) ==>(x1, y1), B(-7, 2) ==> (x2, y2)

Slope (m1)=y2-y1x2-x1= (2-6)(-7+5)= -4-2=2

Slope of CD:

C(7, 1) ==>(x1, y1), D(4, -5) ==> (x2, y2)

Slope (m1)=y2-y1x2-x1= (-5-1)(4-7)= -6-3=2

Slope of AB = Slope of CD

2 = 2

So, slope of the lines AB and CD are equal.

Hence, the line AB is parallel to CD.

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