Volume of pyramid = (1/3) × Base area × Height
For rectangular pyramid,
Base Area = Length × Width
= (1/3) × Length × Width × Height
For triangular pyramid,
Base Area = 1/2 × base × height
= (1/3) × (1/2) × base × height_{ }× Height
Find the volume of the following Pyramid.
Problem 1 :
Solution :
Formula to find volume of pyramid is
= (1/3) × Base area × Height
Here Base Area is the rectangular shape.
So, Base Area = length × width
= (1/3) × length × width × Height
We have,
Length = 2 ft, Width = 1 ft, and Height = 2 ft
= (1/3) × 1 × 2 × 2
= 4/3
V = 1.33 ft³
Problem 2 :
Solution :
Formula to find volume of pyramid is
= (1/3) × Base area × Height
Base area of the pyramid = 15mm²
Height of the pyramid = 4 mm.
Then, volume of the pyramid is
= (1/3) × 15 × 4
V = 20 mm³
Problem 3 :
Solution :
Volume = (1/3) × Base area × Height
Here Base Area is the triangular shape.
So, Base Area = 1/2 × base × height
Here base = 5 yd, height (h_{1}) = 4 yd
= 1/2 × 5 × 4
= 10 yd^{2}
We have,
Base Area = 10 yd^{2 }and Height = 8 yd
= (1/3) × 10 × 8
= (80)/3
V = 26.66 yd³
Problem 4 :
Solution :
Volume = (1/3) × Base area × Height
Here Base Area is the triangular shape.
So, Base Area = 1/2 × base × height
Here base = 10 in, height (h_{1}) = 6 in
= 1/2 × 10 × 6
= 30 in^{2}
We have,
Base Area = 30 in^{2 }and Height (h_{2})= 8 in
= (1/3) × 30 × 8
V = 80 in³
Problem 5 :
Solution :
Volume = (1/3) × Base area × Height
Here Base Area is the rectangular shape.
So, Base Area = length × width
= (1/3) × length × width × Height
We have,
Length = 3 cm, Width = 1 cm, and Height = 7 cm
= (1/3) × 3 × 1 × 7
V = 7 cm³
Problem 6 :
Solution:
Volume = (1/3) × Base area × Height
Base of the pyramid = 63mm²
Height of the pyramid = 12 mm.
= (1/3) × 63 × 12
V = 252 mm³
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