Problem 1:
Without simplifying, find:
The 6th term of (2x + 5)15
Problem 2 :
The 4th term of (x² + 5/x)9
Problem 3 :
The 10th term of (x - 2/x)17
Problem 4 :
The 9th term of (2x² - 1/x)21
Problem 5 :
Find the coefficient of:
x10 in the expansion of (3 + 2x²)10
Problem 6 :
x3 in the expansion of (2x² - 3/x)6
Problem 7 :
x12 in the expansion of (2x² - 1/x)12
Problem 8 :
Find the constant term in:
The expansion of (x + 2/x²)15
Problem 9 :
The expansion of (x - 3/x²)9
1) T6 = 15C5 (2x)10 (5)5
2) T4 = 9C3 (x²)6 (5/x)3
3) T10 = 17C9 (x)8 (-2/x)9
4) T9 = 21C8 (2x²)13 (-1/x)8
5) So, coefficient of x10 is
10C5 35 25
6) So, coefficient of x3 is
6C3 23 (-3)3
7) So, coefficient of x12 is
12C4 28 (-1)4
8) So, the constant term is
15C5 25
9) So, the constant term is
9C3 (-3)3
Problem 1:
Find the coefficient of x5 in the expansion of
(x + 3) (2x - 1)6.
Problem 2 :
Find the coefficient of x5 in the expansion of
(x + 2) (x² + 1)8.
Problem 3 :
Find the coefficient of x6 in the expansion of
(2 - x) (3x + 1)9
Problem 4 :
Find the constant term in the expansion of (3x² + 1/x)8.
Problem 5 :
Find the coefficient of x-6 in the expansion of (2x - 3/x²)12.
Problem 6 :
Find the coefficient of x5 in the expansion of
(2x + 3) (x - 2)6.
Problem 7 :
Find the possible values of a if the coefficient of x³ in
(2x + 1/ax²)9 is 288.
Problem 8 :
Find the term independent of x in the expansion of
(3x - 2/x²)6.
1) So, coefficient of x5 is -336.
2) 28
3) So, coefficient of x6 is 91854.
4) It does not have one.
5) So, coefficient of x-6 is 12C6 (2)6 (-3)6.
6) So, coefficient of x5 is 84.
7) So, value of a is ± 4.
8) 3rd term = 4860.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM