FIND THE PRODUCT BY SUITABLE REARRANGEMENT

Problem 1 :

Find :

25 × 8358 × 4

Solution :

25 × 8358 × 4

Here by multiplying 25 and 4, we will get 100.

= (25 x 4) x 8358

= 100 x 8358

= 835800

Problem 2 :

625 × 3759 × 8

Solution :

= 625 × 3759 × 8

Here by multiplying 625 and 8, we will get 1000.

= (625 x 8) x 3759

= 1000 x 3759

= 3759000

Problem 3 :

Find the product by suitable rearrangement:

 2 × 1768 × 50

Solution :

=  2 × 1768 × 50

Here by multiplying 2 and 50, we will get 100.

= (2 x 50) x 1768

= 100 x 1768

= 176800

Problem 4 :

4 × 166 × 25

Solution :

= 4 × 166 × 25

Here by multiplying 4 and 25, we will get 100

= (4 x 25) x 166

= 100 x 166

= 16600

Problem 5 :

8 × 291 × 125

Solution :

= 8 × 291 × 125

By multiplying 8 and 125, we will get 1000.

= (8 x 125) x 291

= 1000 x 291

= 291000

Problem 6 :

625 × 279 × 16

Solution :

= 625 × 279 × 16

Here by multiplying 625 and 16, we will get 10000

= 10000 x 279

= 2790000

Problem 7 :

285 × 5 × 60

Solution :

= 285 × 5 × 60

Here by multiplying 5 and 60, we will get 300.

= 285 x (5 x 60)

= 285 x 300

= 85500

Problem 8 :

125 × 40 × 8 × 25

Solution :

= 125 × 40 × 8 × 25

By multiplying 125 and 8, we will get 1000.

By multiplying 4 and 25, we will get 100.

= (125 x 8) × (40 × 25)

= 1000 x 100

= 100000

Find the product by suitable rearrangement:

Problem 9 :

A box contains 5 strips having 12 capsules of 500 mg medicine in each capsule. Find the weight in grams of medicine in 32 such boxes.

Solution :

Number of strips = 5

Number of capsules in each strip = 12

Quantity of medicine in each capsule = 500 mg

Number of boxes of medicine available = 32

Total weight of medicine

= number of strips x number of capsule in each x quantity of medicine in each capsule x 32

= 5 x 12 x 500 x 32

= 60 x 500 x 32

= 30000 x 32

= 960000

1 gram = 1000 mg

= 960000 / 1000

= 960 grams

So, 960 grans.

Problem 10 :

Bricks are arranged in 27 heaps in work site for construction. Each heap have 28 bricks. If 8 bricks are taken from each heap for construction, how many bricks are left?

Solution :

Number of heaps in work site = 27

Number of bricks in each heap = 28

Number of bricks required = 27 x 28

= 27 x (20 + 8)

= 27 x 20 + 8 x 27

= 540 + 216

= 756

Number of bricks taken = 8

Number of bricks left over = 756-8

= 748 bricks

Problem 11 :

Find the product by suitable rearrangement:

2 x 1768 x 50

Solution :

= 2 x 1768 x 50

Here we know that multiplying 2 and 50, we will get 100.

= 2 x 50 x 1768

= 100 x 1768

= 176800

Problem 12 :

Multiply by suitable arrangement: 250 , 8, 4, 7

Solution :

= 250 x 8 x 4 x 7

Here by multiplying 250 and 4, we will get 100

= (250 x 4) x (8 x 7)

= 1000 x 56

= 56000

Problem 13 :

The number of students in each class of a school is 25. The fees paid by each student are $928 per month. If there are 20 classes in a school. What is the total fee collection in a month? 

Solution :

Number of students in each class = 25

Amount paid by each student = $928

Number of classes = 20

Total fee collected = 25 x 928 x 20

= (25 x 20) x 928

= 500 x 928

= 5 x 928 x 100

= 4640 x 100

= 464000