The Formula for the Perimeter of a Triangle,
Perimeter = a + b + c
(where a, b, and c are the sides of a triangle)
Problem 1 :
Solution :
Perimeter of triangle = a + b + c
Here, a = 4/7 m, b = 7/8 m and c = 9/8 m
= 4/7 m + 7/8 m + 9/8 m
= (4/7 + 7/8 + 9/8) m
LCM of 7, 8 and 8 is 56
= 32/56 + 49/56 + 63/56 m
= (144)/56 m
=18/7 m
Converting improper fraction into mixed fraction,
= 2 4/7 m
So, the perimeter of a triangle is 18/7 m or 2 4/7 m.
Problem 2 :
Solution :
Perimeter of triangle = a + b + c
Here a = 2/3 cm, b = 2/3 cm and c = 4/9 cm
= 2/3 cm + 2/3 cm + 4/9 cm
= (2/3 + 2/3 + 4/9) cm
LCM of 3, 3 and 9 is 9
= 6/9 + 6/9 + 4/9 cm
= 16/9 cm
Converting improper fraction into a mixed fraction,
= 1 7/9 cm
So, the perimeter of a triangle is 16/9 cm or 1 7/9 cm.
Problem 3 :
Solution :
Perimeter of triangle = a + b + c
Here a = 1 1/4 mm, b =1 1/4 mm and c =1 1/4 mm
=1 1/4 mm +1 1/4 mm +1 1/4 mm
= (5/4 + 5/4 + 5/4) mm
= 15/4 mm
= 3 3/4 mm
So, the perimeter of a triangle is 15/4 mm or 3 3/4 mm.
Problem 4 :
Solution :
Perimeter of triangle = a + b + c
Here a = 3/8 mm, b = 3/8 mm and c = 1/5 mm
= 3/8 mm + 3/8 mm + 1/5 mm
= (3/8 + 3/8 + 1/5) mm
LCM of 8, 8 and 5 is 40
= 15/40 + 15/40 + 8/40 mm
= 38/40 mm
= 19/20 mm
So, the perimeter of a triangle is 19/20 mm.
Problem 5 :
Solution :
Perimeter of triangle = a + b + c
Here a = 9/7 m, b = 9/7 m and c = 9/7 m
= 9/7 m + 9/7 m + 9/7 m
= (9/7 + 9/7 + 9/7) m
= 27/7 m
= 3 6/7 m
So, the perimeter of a triangle is 27/7 m or 3 6/7 m.
Problem 6 :
Solution :
Here a = 3 1/3 cm, b = 3/4 cm and c = 7/2 cm
= 3 1/3 cm + 3/4 cm + 7/2 cm
= (10/3 + 3/4 + 7/2) cm
LCM of 3, 4 and 2 is 12
= 40/12 + 9/12 + 42/12 cm
= 91/12 cm
= 7 7/12 cm
So, the perimeter of a triangle is 91/12 cm or 7 7/12 cm.
Problem 7 :
Solution :
Here a = 5/3 cm, b = 5/3 cm and c = 5/3 cm
= 5/3 cm + 5/3 cm + 5/3 cm
= (5/3 + 5/3 + 5/3) cm
= 15/3 cm
= 5 cm
So, the perimeter of a triangle is 5 cm.
Problem 8 :
Solution :
Here a = 3 mm, b = 5/4 mm and c = 2 1/2 mm
= 3 mm + 5/4 mm + 2 1/2 mm
= (3 + 5/4 + 5/2) mm
= 3 + (5/4 + 5/2)
= 3 + (15/4)
= (12 + 15) / 4
= 27/4 mm
= 6 3/4 mm
So, the perimeter of a triangle is 27/4 mm or 6 3/4 mm.
Problem 9 :
Solution :
Here a = 2 m, b = 6/5 m and c = 6/5 m
= 2 m + 6/5 m + 6/5 m
= (2 + 6/5 + 6/5) m
= (2 + 12/5) m
= 22/5 m
= 4 2/5 m
So, the perimeter of a triangle is 22/5 m or 4 2/5 m.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM