In the following parallelogram AB is base and the line drawn from D to AB is height.
Area of parallelogram = Base x height
Problem 1 :
For the parallelogram ABCD, what is DE to the nearest tenth?
Solution :
Area of parallelogram = Base x height
Base (AB) = 9.4 in and height (DE) = ?
Base (AD) = 13 in and height (CF) = 9 in
9.4 x DE = 13 x 9
DE = (13 x 9)/9.4
DE = 12.4 in
Problem 2 :
Solution :
Area of the parallelogram = base x height
When base = 14, height = 5
When base = 10, height = ?
Let h be the required height.
14 x 5 = 10 x h
h = (14 x 5)/10
h = 7
So, the required height is 7.
Problem 3 :
Solution :
When base = 0.4, height = 0.3
When base = 0.5 and height = h
0.4 x 0.3 = 0.5 x h
h = (0.4 x 0.3)/0.5
h = 0.24
So, the required height is 0.24.
Problem 4 :
Solution :
When base = 13, height = h
When base = 18, height = 12
13 x h = 18 x 12
h = (18 x 12)/13
h = 16.61
So, the required height is 16.61.
Problem 5 :
The area of a parallelogram is 24 in^{2}, and the height is 6 in. Find the length of the corresponding base.
Solution :
Area of parallelogram = 24 in^{2}
height = 6 in
Let base = b
b x 6 = 24
b = 24/6
b = 4 in
So, the required base is 4 inches.
Problem 6 :
Find the area of the composite figure. Then find the area.
Solution :
The shape given above includes two basic shapes, parallelogram and right triangle.
Area of the shape = Area of parallelogram + area of triangle
Base of the parallelogram = 7 m and height = 6 m
Base of right triangle = 5 m and height = 6 m
= 7 x 6 + (1/2) x 5 x 6
= 42 + 15
= 57 m^{2}
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM