FIND THE MEASURE OF EACH INTERIOR ANGLE OF A REGULAR POLYGON

Regular polygon has all sides equal in length and all angles equal in size.

The sum of interior angles of n sided polygon is 

s = (n - 2) x 180°

Measure of each angle= (n-2)×180n

Problem 1 :

For the following regular polygon given below,

a) Equilateral triangle

b) Square

c) Pentagon

d)  Hexagon

e) Octagon

f) Decagon

find

(i)  Number of sides that the polygon has

(ii) Number of angles

(iii)  Size of each angle.

Solution :

a) Equilateral triangle

Number of sides = 3, number of angles = 3

Measure of each angle= (3-2)×1803Each angle measure of equilateral triangle= 1803= 60°

b) Square

Number of sides = 4, number of angles = 4

Measure of each angle= (4-2)×1804Each angle measure of square = 3604= 90°

c) Pentagon

Number of sides = 5, number of angles = 5

Measure of each angle= (5-2)×1805Each angle measure of pentagon = 5405= 108°

d) Hexagon

Number of sides = 5, number of angles = 5

Measure of each angle= (6-2)×1806Each angle measure of hexagon = 7206= 120°

e) Octagon

Number of sides = 8, number of angles = 8

Measure of each angle= (8-2)×1808Each angle measure of octagon = 7208= 135°

f) Decagon

Number of sides = 10, number of angles = 10

Measure of each angle= (10-2)×18010Each angle measure of decagon = 144010= 144°

Problem 2 :

Find the size of each angle of a regular 12 sided polygon.

Solution :

Sum of interior angles of 12 sided polygon = (12 - 2) x 180

= 10 x 180

= 1800

Each angle measure = 1800/12

= 150

So, the size of each angle of a 12 sided regular polygon is 150 degree.

Problem 3 :

Each exterior angle of a regular polygon is 20⁰. Work out the number of sides of the polygon.

Solution :

Exterior angle of a regular polygon = 20

Interior angle = 180 - 20

Each interior angle = 160

160= (n-2)×180n160n180 = n - 28n9 = n - 22 = n -8n92 =9n - 8n92 =n9n = 18

So, the polygon will have 18 sides.

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