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Problem 1 :
Identify the values of the domain for the following relation :

A) {-2, 0, 1, 3} B) {-3, -2, 0, 1, 2}
C) {-2, -1, 0, 1, 2, 3} D) {-3, 0, 1, 2}
Problem 2 :
Identify the values for the domain of the function :

A) {-2, -1,
0, 1, 2}
B) {(1, -2), (-1, -1), (2, 0), (1, 1), (2, 2)}
C) {-1, 1, 2}
D) {(-2, 1), (-1, -1), (0, 2), (1, 1), (2, 2)}
Problem 3 :
List the range for the following function.
{(2, 3), (4, 5), (3, 4), (7, 8)}
A) {3, 4, 5, 8} B) {2, 3, 4, 7}
C) {2, 3, 4, 5, 7, 8} D) {2, 3, 3, 4, 4, 5, 7, 8}
Problem 4 :
Identify the values of the range for the following relation :
{(2, 3), (5, 7), (7, 9), (4, 8)}
A) {2, 5, 7, 4} B) {2, 3, 4, 8}
C) {2, 8} D) {3, 7, 9, 8}
Problem 5 :
Identify the range for the following relation :

A) {-2, -1, 3, 5} B) {-1, 0, 4, 7}
C) {-2, -1, 0, 3, 4, 5, 7} D) {0, 1, 4, 7}
Problem 6 :
To graph the equation y = 3x - 7,
Renita created the following table of values.

Which y
-value corresponds to 7?
A) 21 B) 28 C) 14 D) -4
Problem 7 :
A relation is graphed as shown.

Find all the values that are in the domain of this relation.
Problem 8 :
Florida’s state marine mammal is the manatee. A manatee eats about 12% of its body weight each day.
a. Write an equation in function form that represents the amount y (in pounds) of food a manatee eats each day for its weight x.
b. Create an input-output table for the equation in part (a). Use the inputs 150, 300, 450, 600, 750, and 900
c. Find the domain and range of the function represented by the table.
d. An aquatic center has manatees that weigh 300 pounds, 750 pounds, and 1050 pounds. How many pounds of food do all three manatees eat in a day? in a week?
Problem 9 :
The number of earrings and headbands you can buy with $24 is represented by the equation 8x + 4y = 24. The table shows the number of earrings and headbands.
a. Write the equation in function form.
b. Find the domain and range.
1) Domain = {-3, 0, 1, 2}
2) Domain = {-2, -1, 0, 1, 2}
3) Range = {3, 4, 5, 8}
4) Range = {3, 7, 9, 8}
5) Range = {4, 0, -1, 7}
6) y = 14
7) Domain = {1, 3, 4, 6}
8) a) y = 0.12x
b)
|
When x = 150 y = 0.12(150) y = 18 |
When x = 300 y = 0.12(300) y = 36 |
When x = 450 y = 0.12(450) y = 54 |
|
When x = 600 y = 0.12(600) y = 72 |
When x = 750 y = 0.12(750) y = 90 |
When x = 900 y = 0.12(900) y = 108 |
c)
|
Domain x 150 300 450 600 750 900 |
Range y 18 36 54 72 90 108 |
d)
|
When y = 300 300 = 0.12x x = 300/0.12 = 2500 |
When y = 750 750 = 0.12x x = 750/0.12 = 6250 |
When y = 1050 1050 = 0.12x x = 1050/0.12 = 8750 |
9) a) y = -2x + 6
b) Domain = {0, 1, 2, 3}
Range = {6, 4, 2, 0}
c) Since we get the negative value that is number of headbands. So, x = 6 cannot be in the domain.
Problem 1 :
D = {-1, 0, 2, 7, 9}, function: ‘add 3’.
Problem 2 :
D = {-2, -1, 0, 1, 2}, function: ‘square and then divide by 2’.
Problem 3 :
D = {x | -2 < x < 2}, function: ‘multiply x by 2 then add 1’.
Problem 4 :
D = {x | -3 ≤ x ≤ 4}, function: ‘cube x’.
Problem 5 :
For the domain {0, 1, 2, 3} and the function ‘subtract 2’, find the range.
Problem 6 :
The domain of the function represented by 2x + y = 8 is −2, 0, 2, 4, and 6. What is the range of the function represented by the table?
Problem 7 :
The table shows the percent y (in decimal form) of the moon that was visible at midnight x days after January 24, 2011.
(a) Interpret the domain and range.
(b) What percent of the moon was visible on January 26, 2011?

or 54% of the moon was visible on January 26, 2011
Problem 8 :
In the sport of vaulting, a vaulter performs a routine while on a moving horse. For each round x of competition, the vaulter receives a score y from 1 to 10.

a. Find the domain and range of the function represented by the table.
b. Interpret the domain and range.
c. What is the mean score of the vaulter?
1) Range = {2, 3, 5, 10, 12}
2) Range = {2, 1/2, 0, 1/2, 2}
3) Range = {-1, 1, 3}
4) Range = {-27, 8, -1, 0, 1, 8, 27, 64}
5) Range = {-2, -1, 0, 1}
6) the range is {12, 8, 4, 0, -4}.
7)
a) Zero days after January 24 is January 24. One day after January 24 is January 25. So, the domain of 0, 1, 2, 3, and 4 represents January 24, 25, 26, 27 and 28.
The range is 0.76, 0.65, 0.54, 0.43, and 0.32. These amounts are decreasing, so the moon was less visible each day.
b. January 26, 2011 corresponds to the input x = 2. When x = 2, y = 0.54. So, 0.54, or 54% of the moon was visible on January 26, 2011
8)
a) Domain = {1, 2, 3}
Range = {6.856, 7.923, 8.135}
b) Here x represents the number of rounds and y represents scores.
c) Mean
= (6.856 + 7.923 + 8.135)/3
= 7.638
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May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM