FIND INVERSE OF LOGARITHMIC FUNCTION

If ƒ is a one-to-one function with domain D and range R, then the inverse function of ƒ, denoted by f-1, is the function with domain R and range D defined by

ƒ-1(b) = a if and only if ƒ(a) = b

To find inverse of a logarithmic function, we follow the steps given below.

Step 1 :

Replace f(x) by y.

Step 2 :

Derive the function for x.

Step 3 :

Replace x by f-1(x) and y by x.

Find the inverse of each of the following functions.

Example 1 :

f(x) = log2(x-3) - 5

Solution :

f(x) = yy= log2(x-3)-5Add 5 on both sides.y + 5 = log2(x-3)Converting into exponential form, we get2y+5 = x - 3Add 3 on both sides.2y+5+3 = xx = 2y+5+3f-1(x)= 2x+5+3

Example 2 :

f(x) = 3log3(x+3) + 1

Solution :

f(x) = yy= 3log3(x+3)+1Subtracting 1 on both sides.y - 1 = 3log3(x+3)Divide by 3 on both sides.y-13= log3(x+3)3y-13= x + 3x = 3y-13 - 3Replacing x by f-1(x) and y by x.f-1(x) = 3x-13 - 3

Example 3 :

f(x) = -2 log 2(x - 1) + 2

Solution :

f(x) = yy= -2log2(x-1)+Subtracting 2 on both sides.y - 2 = -2log2(x-1)Divide by -2 on both sides.y-2-2= log2(x-1)2-y2= 2(x-x-1 = 12102-y2x= 12102-y2Replacing x by f-1(x) and y by x.f-1(x) = 12102-x2

Example 4 :

f(x) = -ln(1 - 2x) + 1

Solution :

f(x) = yy= -ln(1- 2x)+Subtracting 2 on both sides.y - 1 = -ln(1-2x)Divide by -1 on both sides.=ln(1-2x)1 - y= 1-2xx= 1-e1 - yx= 1-e1-yReplacing x by f-1(x) and y by x.f-1(x) = 1-e1-xf-1(x) = 1e1-x

Example 5 :

f(x) = 2x - 3

Solution :

Let y = f(x)

y = 2x - 3

Add 3 on both sides

y + 3 = 2x

log2(y + 3) = x

f-1(x) = log2(x + 3)

Example 6 :

f(x) = 2 ⋅33x - 1

Solution :

f(x) = yy= 233x-1Adding 1 on both sides.y+1 = 233xDivide by 2 on both sides.y+12 = 33xlog3y+12= 3xx = 13log3y+12Replacing x by f-1(x) and y by x.f-1(x) = 13log3x+12

Example 7 :

f(x) = -5 ⋅ex + 2

Solution :

y = -5 ⋅ex + 2

y - 2 = -5 ⋅ex

2 - y = 5ex

(2 - y)/5 = ex

x = ln [(2 - y)/5]

f-1(x) = ln [(2 - x)/5]

Example 8 :

f(x) = 1 - 2 ⋅e-2x

Solution :

y = 1 - 2 ⋅e-2x

⋅e-2x = 1 - y

e-2x = (1 - y)/2

-2x = ln [(1 - y)/2]

x = (-1/2) ln [(1 - y)/2]

f-1(x) = (-1/2) ln [(1 - x)/2]

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