FIND INVERSE OF LOGARITHMIC FUNCTION

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

If ƒ is a one-to-one function with domain D and range R, then the inverse function of ƒ, denoted by f-1, is the function with domain R and range D defined by

ƒ-1(b) = a if and only if ƒ(a) = b

To find inverse of a logarithmic function, we follow the steps given below.

Step 1 :

Replace f(x) by y.

Step 2 :

Derive the function for x.

Step 3 :

Replace x by f-1(x) and y by x.

Find the inverse of each of the following functions.

Example 1 :

f(x) = log2(x - 3) - 5

Solution :

f(x) = yy= log2(x-3)-5Add 5 on both sides.y + 5 = log2(x-3)Converting into exponential form, we get2y+5 = x - 3Add 3 on both sides.2y+5+3 = xx = 2y+5+3f-1(x)= 2x+5+3

Example 2 :

f(x) = 3 log3(x + 3) + 1

Solution :

f(x) = yy= 3log3(x+3)+1Subtracting 1 on both sides.y - 1 = 3log3(x+3)Divide by 3 on both sides.y-13= log3(x+3)3y-13= x + 3x = 3y-13 - 3Replacing x by f-1(x) and y by x.f-1(x) = 3x-13 - 3

Example 3 :

f(x) = -2 log 2(x - 1) + 2

Solution :

f(x) = yy= -2log2(x-1)+Subtracting 2 on both sides.y - 2 = -2log2(x-1)Divide by -2 on both sides.y-2-2= log2(x-1)2-y2= 2(x-x-1 = 12102-y2x= 12102-y2Replacing x by f-1(x) and y by x.f-1(x) = 12102-x2

Example 4 :

f(x) = -ln(1 - 2x) + 1

Solution :

f(x) = yy= -ln(1- 2x)+Subtracting 2 on both sides.y - 1 = -ln(1-2x)Divide by -1 on both sides.=ln(1-2x)1 - y= 1-2xx= 1-e1 - yx= 1-e1-yReplacing x by f-1(x) and y by x.f-1(x) = 1-e1-xf-1(x) = 1e1-x

Example 5 :

f(x) = 2x - 3

Solution :

Let y = f(x)

y = 2x - 3

Add 3 on both sides

y + 3 = 2x

log2(y + 3) = x

f-1(x) = log2(x + 3)

Example 6 :

f(x) = 2 ⋅33x - 1

Solution :

f(x) = yy= 233x-1Adding 1 on both sides.y+1 = 233xDivide by 2 on both sides.y+12 = 33xlog3y+12= 3xx = 13log3y+12Replacing x by f-1(x) and y by x.f-1(x) = 13log3x+12

Example 7 :

f(x) = -5 ⋅ex + 2

Solution :

y = -5 ⋅ex + 2

y - 2 = -5 ⋅ex

2 - y = 5ex

(2 - y)/5 = ex

x = ln [(2 - y)/5]

f-1(x) = ln [(2 - x)/5]

Example 8 :

f(x) = 1 - 2 ⋅e-2x

Solution :

y = 1 - 2 ⋅e-2x

⋅e-2x = 1 - y

e-2x = (1 - y)/2

-2x = ln [(1 - y)/2]

x = (-1/2) ln [(1 - y)/2]

f-1(x) = (-1/2) ln [(1 - x)/2]

Example 9 :

The wind speed s (in miles per hour) near the center of a tornado can be modeled by s = 93 log d + 65, where d is the distance (in miles) that the tornado travels.

a. In 1925, a tornado traveled 220 miles through three states. Estimate the wind speed near the center of the tornado.

b. Find the inverse of the given function. Describe what the inverse represents

inverse-of-log-function-q1

Solution :

s = 93 log d + 65

Here d is the distance (in miles) that the tornado travels.

s is the wind speed s (in miles per hour)

a) When d = 220 miles, s = ?

s = 93 log 220 + 65

s = 93(2.342) + 65

= 217.806 + 65

= 282.806

So, the required speed 283 miles per hour.

b) 

s = 93 log d + 65

s - 65 = 93 log d

(s - 65)/93 = log d

d = 10(s - 65)/93

The function represents distance traveled with the speed of s miles per hour.

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

Recent Articles

  1. Finding Range of Values Inequality Problems

    May 21, 24 08:51 PM

    Finding Range of Values Inequality Problems

    Read More

  2. Solving Two Step Inequality Word Problems

    May 21, 24 08:51 AM

    Solving Two Step Inequality Word Problems

    Read More

  3. Exponential Function Context and Data Modeling

    May 20, 24 10:45 PM

    Exponential Function Context and Data Modeling

    Read More