# FIND EQUATION OF PARABOLA GIVEN FOCUS AND DIRECTRIX WORKSHEET

Problem 1 :

Write the equation of parabola which has focus at (3, 8) and directrix at y = 4.

Solution

Problem 2 :

Write the equation of parabola which has focus at (2, -3) and directrix at x = 5

Solution

Problem 3 :

Write the equation of parabola which has focus at (-4, -2) and directrix at x = -8

Solution

1)  the required equation of parabola is (x - 3)2 = 8(y - 6).

2)  the required equation of parabola is

(y + 3)2 = -6 (y - 3.5)

3)  the required equation is (y + 2)2 = 8 (x + 6) .

Problem 1 :

Write the equation the parabola  with vertex (-7, 4), axis of symmetry x = -7 and measure of latus rectum 6. a < 0

Solution

Problem 2 :

Write the equation the parabola  with vertex (4, 3), axis of symmetry y = 3 and measure of latus rectum 4. a > 0

Solution

Problem 3 :

In the parabola shown in the graph, the point (2, -2) is called the _____ and the point (2, 0) is called the ____.

a)  The line  y = -4 is called the _________

b) The line x = 2 is called the _________

Solution

Problem 4 :

Write the equation the parabola  with vertex (1, 3), axis of symmetry x = 1 and measure of latus rectum 2. a < 0

Solution

1)  y2 - 8y  + 6x + 58 = 0

2)  x2 -  8x - 4y + 28 = 0

3)  In the parabola shown in the graph, the point (2, -2) is called the Vertex and the point (2, 0) is called the Focus

a)  The line  y = -4 is called the directrix

b) The line x = 2 is called the axis of symmetry

4)  y2  - 6y + 2x + 7 = 0

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