EXPRESSING A NUMBER AS A PERCENTAGE OF ANOTHER

To express the number as percentage of other, we will follow the steps given below.

(i) Write the given quantities as fraction

(ii)  To convert the fraction as percentage, we will multiply it by 100%.

Problem 1 :

For every 50 students at Hightown School, 29 are girls.

(a) Work out 29 as a percentage of 50.

1000 students attend Hightown School.

(b) How many girls attend Hightown School?

Solution :

(a) Total number of students = 50, number of girls = 29

Expressing it as percentage = 29/50 (Out of 50, 29 are girls)

To convert 50 as 1000, we will multiply 50 by 20, so the numerator also be multiplied by 20. We get

= (29/50) ⋅ (20/20)

= 580/1000

So, 580 girls are there.

Problem 2 :

David receives $5 from his Grandmother. He gives $2 to his sister. Write down $2 as a percentage of $5.

Solution :

Money received from his grand mother = $5

Amount given to his sister = $2

Expressing it as percentage, we get

= (2/5) ⋅ 100%

= 40%

Problem 3 :

Roger scores 6 out of 8 in a quiz. Work out his score as a percentage.

Solution :

Total score = 8, He has scored = 6

Expressing it as percentage,

= (6/8) ⋅ 100%

= 75%

Problem 4 :

Susan brings 500 flapjacks to a local fair. Susan sells 450 of the flapjacks. What percentage of the flapjacks did Susan sell?

Solution :

Number of flapjacks = 500

Number of flapjack he sells = 450

Expressing it as percentage = (450/500) x 100%

= 90%

Problem 5 :

Write 94 out of 200 as a percentage.

Solution :

94 out of 200 = (90/200)

Expressing it as percentage = (90/200) x 100%

= 45%

Problem 6 :

Colin gains 13 out of 20 in a class test. Work out his mark as a percentage.

Solution :

Total score = 20

Collin gains = 13

Expressing as fraction = 13/20

Expressing as percentage = (13/20) x 100%

= (13 x 5) %

= 65%

Problem 7 :

There are 600 people at a football match. There 222 children at the match. Write 222 out of 600 as a percentage.

Solution :

Total number of people = 600

Number of children in the match = 222

Expressing as fraction, we get

= (222/600)

Expressing as percentage = (222/600) x 100%

= 37%

Problem 8 :

Bryan buys a car costing $15000. He pays a deposit $6000. What is $6000 as a percentage of $15000?

Solution :

Cost of car = $15000

Deposit = $6000

Expressing as percentage = (6000/15000) x 100%

= 40%

Problem 9 :

The price of a cinema ticket is reduced from $8 to $7.50 Calculate the reduction as a percentage of the original price

Solution :

Price of ticket = $8

Price of ticket after reduction = $7.50

Difference in price = 8 - 7.50

= 0.50

Expressing the reduction as percentage of original price

= (0.50/8) x 100%

= 6.25%

Problem 10 :

The population of a country is 2.85 x 10⁶. The number of people that own a rabbit is 1.24 x 10⁵. Calculate the percentage of the population that own a rabbit.

Solution :

Total population = 2.85 x 10⁶

People that own rabbit = 1.24 x 10⁵

Percentage of population that own rabbit

= (1.24 x 10⁵)/(2.85 x 10⁶) x 100%

= (124000/2850000) x 100%

= 4.35%

Problem 11 :

The width of a rectangular room is 80% of its length. What is the area of the room?

percentage-of-another-q1

Solution :

Length of rectangular room = 15 ft

Width = 80% of length

= 80/100 of 150

= 0.80(15)

= 12 ft

Area of rectangular room = length x width

= 12 x 15

= 180 square ft

Problem 12 :

Lake Worth, near West Palm Beach, had about 2120 acres of mangrove trees 40 years ago. Only about 13% of the mangrove trees remain. How many acres of mangrove trees remain?

Solution :

Area of mangrove trees = 2120 

13% of mangrove trees remain = 13% of 2120

= 13/100 x 2120

= 0.13 (2120)

= 275.6

approximately 276 acres.

Problem 13 :

The price of a bicycle after a 25% discount is $679.99. What was the original price? Round to the nearest cent.

Solution :

Let x be the original price of bicycle.

After reducing 25%, we get 75% of the original price = 679.99

0.75 of x = 679.99

0.75x = 679.99

x = 679.99/0.75

= 906.65

So, original price of the bicycle is $907 approximately.

Problem 14 :

After a tune up a car produced 5% more horsepower. If the horsepower after the tune up is 525, what was the horsepower before the tune up?

Solution :

Let x be 100% of the horsepower before tue up.

105% of x = 525

1.05 x = 525

x = 525/1.05

x = 500

At the beginning the quantity of horse power is 500.

Problem 15 :

The new model of a car is 12% cheaper than the previous model. If the current model costs $56300, what was the price of the previous model? Round to the nearest cent.

Solution :

Let x be the original price of the precious model

(100 - 12)% of x = 56300

88% of x = 56300

0.86x = 56300

x = 56300/0.86

x = 65465

So, the original price of the model is $65465.

Problem 16 :

After a 7% raise in weekly salary, Matt is now making $1450 per week. What was Matt’s weekly salary before the raise? Round to the nearest cent.

Solution :

Let x be the original salary.

Salary per week now = 107% of x

107% of x = 1450

1.07x = 1450

x = 1450/1.07

x = 1355.14

So, before raise he may recieve $1355.1 approximately.

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