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To express the given number in index form, we have to decompose the number as prime factors.
If we have repeated values, using exponents we can write down it.
For example,
5 x 5 x 5 = 53
Express the following as the product of prime factors in index form:
Problem 1 :
56
Solution :
56 = 8 × 7
= 2 × 2 × 2 × 7
= 23 × 7
Problem 2 :
240
Solution :
240 = 16 × 15
= 4 × 4 × 3 × 5
= 2 × 2 × 2 × 2 × 3 × 5
= 24 × 3 × 5
Problem 3 :
504
Solution :
504 = 72 × 7
= 8 × 9 × 7
= 2 × 2 × 2 × 3 × 3 × 7
= 23 × 3² × 7
Problem 4 :
735
Solution :
735 = 15 × 49
= 3 × 5 × 7 × 7
= 3 × 5 × 7²
Problem 5 :
297
Solution :
297 = 27 × 11
= 9 × 3 × 11
= 3 × 3 × 3 × 11
= 33 × 11
Problem 6 :
221
Solution :
221 = 13 × 17
Problem 7 :
360
Solution :
360 = 72 × 5
= 8 × 9 × 5
= 2 × 2 × 2 × 3 × 3 × 5
= 23 × 3² × 5
Problem 8 :
952
Solution :
952 = 56 × 17
= 8 × 7 × 17
= 2 × 2 × 2 × 7 × 17
= 23 × 7 × 17
Problem 9 :
Express each of the following products in index form
a) 2 x 2 x 2
b) 4 x 4
c) a x a x a x a
d) k x k x k
e) 10 x 10
f) 2 x 2 x 2 x 2 x 2 x 2
g) b x b x b x b x b
h) y x y x y x y x y x y x y x y
Solution :
a) 2 x 2 x 2
Since 2 is repeating three times, then the required index form is 23.
b) 4 x 4
Since 4 is repeating two times, then the required index form is 42.
c) a x a x a x a
Since a is repeating four times, then the required index form is a4.
d) k x k x k
Since k is repeating three times, then the required index form is k3.
e) 10 x 10
Since 10 is repeating two times, then the required index form is 102.
f) 2 x 2 x 2 x 2 x 2 x 2
Since 2 is repeating six times, then the required index form is 26.
g) b x b x b x b x b
Since b is repeating five times, then the required index form is b5.
h) y x y x y x y x y x y x y x y
Since y is repeating eight times, then the required index form is y8.
Problem 10 :
Write the following in expanded form
|
a) 82 b) 35 c) a4 d) y3 |
e) 53 f) 94 g) t6 h) b5 |
Solution :
a) 82 = 8 x 8
b) 35 = 3 x 3 x 3 x 3 x 3
c) a4 = a x a x a x a
d) y3 = y x y x y
e) 53 = 5 x 5 x 5
f) 94 = 9 x 9 x 9 x 9
g) t6 = t x t x t x t x t x t
h) b5 = b x b x b x b x b
Problem 11 :
Evaluate the following
a) 24
c) 32
b) 53
d) 120
Solution :
a) 24 = 2 x 2 x 2 x 2
= 16
b) 32 = 3 x 3
= 9
c) 53 = 5 x 5 x 5
= 125
d) 120
Multiplying 1 by any number of times, we get 1.
Problem 12 :
Write the prime factors of these numbers in index form
a) 20
c) 36
b) 96
d) 100
Solution :
a) 20 = 2 x 2 x 5
= 22 x 5
b) 36 = 3 x 3 x 2 x 2
= 32 x 22
c) 96 = 3 x 2 x 2 x 2 x 2 x 2
= 3 x 25
d) 100 = 5 x 5 x 2 x 2
= 52 x 22
Problem 13 :
Write the following in index form
a) 2 x a x b x a x 2 x a x 2 x b
b) 4d x 2f x 4d x 2f
c) 2cd(2cd)(2cd)(2cd)
d) 3a x 2b x 3a x 2b
e) 5ab(5ab)5b
f) 7ab x 7ab x ab x 7
Solution :
a) 2 x a x b x a x 2 x a x 2 x b = 23 x a3 x b2
b) 4d x 2f x 4d x 2f = (2f)2 x (4d)2
c) 2cd(2cd)(2cd)(2cd) = (2cd)4
d) 3a x 2b x 3a x 2b = (3a)2 x (2b)2
e) 5ab(5ab)5b = (5b)3 x a2
f) 7ab x 7ab x ab x 7 = 73 x (ab)3
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May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM