# EXPONENTIAL FUNCTION CONTEXT AND DATA MODELLING WORKSHEET

For each problem, create a function to model the scenario.

Problem 1 :

A population π of 500 people doubles every 35 years π‘.

Solution

Problem 2 :

Mr. Kelly bought a new tractor for his farm in New York. It cost him \$150,000. Unfortunately, itβs value π£ depreciates in value by 5.4% per year π‘.

Solution

Problem 3 :

A baseball card is worth \$50 and its value π£ increases at a rate of 23.5% per year π‘

Solution

Problem 4 :

There is 500 grams π of radioactive material. Its halflife is 5,700 years, π‘

Solution

Problem 5 :

700 grams of radioactive material π decays at a rate of 2.4% per year π‘. How much material will be there after 100 years ?

Solution

Problem 6 :

The new tires on a truck have a tread depth of 0.5 inches and decays at the rate of 1.6% per week. How deep will the tread be after 52 weeks ?

Solution

Problem 7 :

A car that is worth \$25000, decreases in value by 15% per year. How much will the car be after 5 years ?

Solution

Problem 8 :

Mr. Brust IQ currently 173, but it is decaying at a rate of 4.5% every year. What will Mr. Brust's IQ be in 20 years ?

Solution

Problem 9 :

A plague of mice has hit Australia! Starting with only 30 mice, their population π increases by 650% every month, π.

Solution

Problem 10 :

The rodent population π in a large city is being controlled by a new poison that kills half the population every 6 months π. There are currently 2,000,000 rodents.

Solution

1)  f(t) = 500 (2)t/35

2)  150000 (0.946)t

3)  50(1.235)t

4)  A = 500 (1/2) t/5700

5)  after 100 years 61.67 grams of material will be there.

6) Approximately 0.22 inches

7) So, the worth of car after 5 years is \$11092.63.

8)   68.88

9)  30(7.5)m

10) A = 2,000,000 (1/2) t/6

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