For each problem, create a function to model the scenario.
Problem 1 :
A population π of 500 people doubles every 35 years π‘.
Problem 2 :
Mr. Kelly bought a new tractor for his farm in New York. It cost him $150,000. Unfortunately, itβs value π£ depreciates in value by 5.4% per year π‘.
Problem 3 :
A baseball card is worth $50 and its value π£ increases at a rate of 23.5% per year π‘
Problem 4 :
There is 500 grams π of radioactive material. Its halflife is 5,700 years, π‘
Problem 5 :
700 grams of radioactive material π decays at a rate of 2.4% per year π‘. How much material will be there after 100 years ?
Problem 6 :
The new tires on a truck have a tread depth of 0.5 inches and decays at the rate of 1.6% per week. How deep will the tread be after 52 weeks ?
Problem 7 :
A car that is worth $25000, decreases in value by 15% per year. How much will the car be after 5 years ?
Problem 8 :
Mr. Brust IQ currently 173, but it is decaying at a rate of 4.5% every year. What will Mr. Brust's IQ be in 20 years ?
Problem 9 :
A plague of mice has hit Australia! Starting with only 30 mice, their population π increases by 650% every month, π.
Problem 10 :
The rodent population π in a large city is being controlled by a new poison that kills half the population every 6 months π. There are currently 2,000,000 rodents.
1) f(t) = 500 (2)^{t/35}
2) 150000 (0.946)^{t}
3) 50(1.235)^{t}
4) A = 500 (1/2) ^{t/5700}
5) after 100 years 61.67 grams of material will be there.
6) Approximately 0.22 inches
7) So, the worth of car after 5 years is $11092.63.
8) 68.88
9) 30(7.5)^{m}
10) A = 2,000,000 (1/2) ^{t/6}
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM