# EVALUATING NUMERICAL EXPRESSIONS USING PROPERTIES WORKSHEET

Problem 1 :

Find the sum by suitable rearrangement:

713 + 200 + 87

Solution

Problem 2 :

Simplify

126 × 45 + 126 × 55

by using suitable property.

Solution

Problem 3 :

Siddharth purchased 10 boxes of chocolates to be distributed among the students. Each package has 10 packets, each of which contains 10 chocolates. Then how many chocolates did he order?

Solution

Problem 4 :

Shelly got 49 marks in Math, 39 marks in English, and 51 in Science. John got 62 marks in Math, 36 in English and 54 in Science. What are their total marks?

Solution

Problem 5 :

Simplify using distributive property:

23 × 99

Solution

Problem 6 :

Simplify by suitable rearrangement:

i) 643 + 346 + 357

ii) 5 × 241 × 20

Solution

Problem 7 :

Simplify the following using the distributive property:

i) 234 × 256 – 234 × 56

ii) 54 × 1001

Solution

Problem 8 :

The cost of a chair is ₹7635 and the cost of a table is ₹12365. Find the total cost of 12 chairs and 12 tables.

Solution

Problem 9 :

Find the sum by suitable rearrangement

47+953+6437

Solution

Problem 10 :

i)

2698 × (100 + 9) = 2698 × 100 + 2698 × 9

is true by _________property.

ii)  Use the same property to solve the expression:

51887 × 88 + 51887 × 12

Solution

Problem 11 :

Identify the property demonstrated by the following statements:

a) 12 + 13 = 13 + 12

b) 10 × (46 + 24) = 10 × 46 + 10 × 24

c) 100 + 0 = 0 + 100 = 100

Solution

1)   1000

2)  12600

3)  number of chocolates he order is 1000.

4)  152

5)  2277

6)  i) 1346    ii)  24100

7)  i)  46800      ii)  54054

8)  cost of 12 chairs and tables is ₹240000

9)  7437

10)   i)  distributive property    ii)  5188700

11)

a) Commutative property.

b) distributive property.

c) identity property.

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