# EQUATION OF PARABOLA WITH VERTEX AND FOCUS WORKSHEET

Find the equation of the parabola that satisfies the given conditions.

Problem 1 :

Vertex (0, 0) and focus (0, -2)

Solution

Problem 2 :

Vertex (3, 2) and focus (3, 6)

Solution

Problem 3 :

Find the vertex and focus of the parabola.

(y - 2)2 + 16(x - 3) = 0

Solution

Problem 4 :

Find the standard form of the equation of the parabola with the given characteristic and vertex at the origin. focus: (0, 7)

Solution

Problem 5 :

Find the equation of the parabola with vertex at (5, 4) and focus at (-3, 4).

Solution

Problem 6 :

A cross section of a parabolic reflector is shown in the figure. The bulb is located at the focus and the opening at the focus is 10 cm.

a) Find the equation of parabola

b) Find the diameter of the opening |CD|, 11 cm from the vertex.

Solution

Find the equation of the parabola. Then find focus and directrix.

Problem 7 :

Problem 8 :

Solution

1)  the required equation of parabola is y2 = 8x.

2)  the required equation of parabola is (y - 2)2 = 16(x - 3)

3) (y - 2)2 = 16(x - 3)

4)  the required equation will be y2 = 28x.

5)  the required equation of parabola is (y - 5)2 = 32(x - 4)

6)  the diameter is 20.96 cm.

7)  y2 = -x, Focus ==> (-1/4, 0)

Equation of directrix ==> x = 1/4

8)  (x - 2)2 = 2(y + 2), Focus ==> (2, -3/2)

Equation of directrix ==> y = -5/2

## Recent Articles

1. ### Finding Range of Values Inequality Problems

May 21, 24 08:51 PM

Finding Range of Values Inequality Problems

2. ### Solving Two Step Inequality Word Problems

May 21, 24 08:51 AM

Solving Two Step Inequality Word Problems