Find the equation of circle with the center and passes through the given point.
Problem 1 :
Center : (11, 0)
Point on Circle : (3, 0)
Problem 2 :
Center : (15, 13)
Point on Circle : (19, 13)
Problem 3 :
Center : (-5, 9)
Point on Circle : (-7, 11)
Problem 4 :
Center : (-11, 11)
Point on Circle : (-15, 17)
Problem 5 :
Find the equation of a circle where the center is at (2, -4), and the point (6, 1) rests on the circle.
Problem 6 :
Find the equation of a circle where the center is at (-2, 3), and the point (1, 4) rests on the circle.
1)
Standard equation of a circle :
(x - 11)^{2} + (y - 0)^{2} = 64
General form of equation of a circle :
x^{2} + y^{2} - 22x + 57 = 0
2)
Standard equation of a circle :
(x - 15)^{2} + (y - 13)^{2} = 16
General form of equation of a circle :
x^{2} + y^{2} - 30x - 26y + 378 = 0
3)
Standard equation of a circle :
(x + 5)^{2} + (y - 9)^{2} = 68
General form of equation of a circle :
x^{2} + y^{2} + 10x - 18y + 38 = 0
4)
Standard equation of a circle :
(x + 11)^{2} + (y - 11)^{2} = 52
General form of equation of a circle :
x^{2} + y^{2} + 22x - 22y + 190 = 0
5)
Standard equation of a circle :
(x - 2)^{2} + (y + 4)^{2} = 41
General form of equation of a circle :
x^{2} + y^{2} - 4x + 8y - 21 = 0
6)
Standard equation of a circle :
(x + 2)^{2} + (y - 3)^{2} = 10
General form of equation of a circle :
x^{2} + y^{2} + 4x - 6y + 3 = 0
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM