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Problem 1 :

A 20 cm wide picture frame surrounds a painting which is 100 cm by 60 cm. Are the two rectangles shown here similar?
Solution :
Picture frame = 20 cm
Surrounds a painting = 100 cm by 60 cm
100 : 60 = 5 : 3
Inside rectangle has sides in 5 : 3
100 + 60 = 160
20 cm wide picture frame = 160 – 20
= 140
140 : 100 = 7 : 5
Outside rectangle has sides in 7 : 5
And 5 : 3 ≠ 7 : 5
Therefore it is not similar.
Give brief reasons why these figures possess similar triangles:
Problem 2 :

Solution :
∠ABE = ∠DEB (Alternate interior angles)
∠ACB = ∠DCE (Vertically opposite angles)
So, triangles are equiangular and therefore, similar.
Problem 3 :

Solution :
∠PQR = ∠STR (given)
∠PQT = ∠STP (Alternate interior angles)
∠PRQ = ∠SRT (Vertically opposite angles)
So, triangles are equiangular and therefore, similar.
Problem 4 :

Solution :
Both triangles are right angled.
∠BAE = ∠EDA (Alternate interior angles)
∠BCA = ∠DCE (Vertically opposite angles)
So, triangles are equiangular and therefore similar.
Problem 5 :

At 4 pm one day the shadow of a pine tree was 5 m long. At the same time a 2 m long broom handle had a shadow which was 3 m long. How high is the pine tree?
Solution :
The shadow of a pine tree = 5 m long
The same time = 2 m long
Broom handle had a shadow = 3 m long
2/3 = x/5
10 = 3x
x = 3.3
So, the pine tree high is 3.3 m.
After establishing similarity, find the unknowns in:
Problem 6 :

Solution :

6/4 = x/2
3/2 = x/2
x = 3
Problem 7 :

Solution :

12/10 = x/4
6/5 = x/4
x = 4.8
Problem 8 :

Solution :

x/4 = 7/3
3x = 28
x = 9 1/3
Problem 9 :
The Mexican flag is 63 inches long and 36 inches high. Is the drawing at below similar to the Mexican flag ?

Solution :
Length of the original flag = 63 inches
Length of flag shown = 11 inches
Width of original flag = 36 inches
Width of flag shown = 8.5 inches
63/11 = 36/8.5
5.72 not equal to 4.23
So, the flag show above is not similar to the original flag.
Problem 10 :
A student’s rectangular desk is 30 inches long and 18 inches wide. The teacher’s rectangular desk is 60 inches long and 36 inches wide. Are the desks similar?
Solution :
Length of student's rectangular desk = 30 inches
Width = 18 inches
Length of teacher's rectangular desk = 60 inches
Width = 36 inches
30 : 60 = 18 : 36
1 : 2 = 1 : 2
Since the corresponding sides are in the same ratio, the desks are similar.
Problem 11 :
The two triangles are similar. Find the measure of the angle
a) ∠B b) ∠L c) ∠J

Solution :
a)
In triangle ABC,
∠A + ∠B + ∠C = 180
42 + ∠B + 90 = 180
132 + ∠B = 180
∠B = 180 - 132
∠B = 48
b) ∠L = 90
c) ∠J = 42
Problem 12 :
Given △FGH ∼ △QRT, name the corresponding angles and the corresponding sides.
Solution :
∠F = ∠Q
∠G = ∠R
∠H = ∠T
Corresponding sides are,
FG and QR
GH and RT
FH and QT
Problem 13 :
You want to buy only photos that are similar rectangles. Which of the photo sizes should you buy ?
4 in × 5 in
5 in × 7 in
8 in × 12 in
11 in × 14 in
18 in × 27 in
Solution :
Comparing the corresponding lengths and widths, we get
8 : 18 = 12 : 27
8/18 = 12/27
4/9 = 4/9
So, we may purchase the photos which has the measure of 8 in × 12 in and 18 in × 27 in.
Problem 14 :
Are the following figures always, sometimes, or never similar? Explain.
a. Two triangles
b. Two squares
c. Two rectangles
d. A square and a triangle
Solution :
a. Two triangles will be similar sometimes
b. All squares have four 90° angles, and since all four sides of a square are equal, any two squares will have sides that are proportional. This makes them always the same shape.
c. While all rectangles have four 90° angles, their sides are not necessarily proportional. So, rectangles will be similar sometimes.
d. A square and a triangle will never be similar.
Problem 15 :
Can you draw two quadrilaterals each having two 130° angles and two 50° angles that are not similar? Justify your answer.
Solution :
Yes, the two quadrilaterals may be one isosceles trapezium and another parallelogram. So, they may not be similar.
Problem 16 :
All of the angle measures in the sign are 90°.
a. Each side length is increased by 20%. Is the new sign similar to the original?
b. Each side length is increased by 6 inches. Is the new sign similar to the original?

Solution :
a) Let the length of the rectangle be x, by increasing 20% of length we get 120% of x
Let width of the rectangle be y, increasing 20% the new width 120% of y
x : 120% x = y : 120% of y
x : 1.20x = y : 1.20y
So, they are similar.
b) After increasing 6 inches, then new length will be x + 6
x : y = (x + 6) : y
So, they are not similar.
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May 21, 24 08:51 PM
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