DEFINITE INTEGRAL INVOLVING SQUARE ROOT

Problem 1 :

Solution :

Problem 2 :

Solution :

Problem 3 :

Solution :

Problem 4 :

Solution :

Problem 5 :

Find the area bounded by 

y = √x, the x-axis, x = 1 and x = 4

Solution :

area-under-the-curve-integral-q1

Problem 6 :

Find the area bounded by 

y = x √x, the x-axis, x = 1 and x = 9

Solution :

y = x (x)1/2

y = x3/2

Applying some random values of x,

When x = 1

y = (1)3/2

y = 1

When x = 4

y = (4)3/2

y = 8

When x = 9

y = (9)3/2

y = 27

Some of the points on the curve are (1, 1) (4, 8) and (9, 27). By connecting these points, we will get

area-under-the-curve-integral-q2.png

Problem 7 :

Solution :

The given shape is a rectangular hyperbola.

area-under-the-curve-integral-q3.png

Solution :

Problem 8 :

Solution :

Problem 9 :

The shaded region has area 5 square units. Find k to the 3 decimal places.

indefinite-integral-with-square-root

Solution :

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