# CONVERT CUSTOMARY UNITS OF LENGTH WORD PROBLEMS

Problem 1 :

Brian was tiling a patio and ran out of tiles. The width of the remaining area is 2/3 yard. The length of the remaining area is 4 yards. What is the area Brian has left to tile ?

Solution :

The length of the remaining area = 4 yards

The width of the remaining area = 2/3 yard

Since, area of the remaining area of the rectangular patio.

a = l × w

= 4 × 2/3

= 8/3

= 2.67 square yards

Therefore, area of the remaining area of the rectangular patio = 2.67 square yards.

Problem 2 :

Rylee knows that the area for the face-painting station is 166 square feet. She knows that the length of the rectangular area is 12 feet. How wide is the area ?

Solution :

area for the face painting station = 166 square feet

length of the rectangular area = 12 feet

a = l × w

166 = 12 × w

166/12 = w

13.83 = w

So, area of the wide is 13.83 feet.

Problem 3 :

Coby needs to know the area and perimeter of his farm property. The length of his property is 1/12 mile and the width is 3/8 mile. What is the area ? what is the perimeter ?

Solution :

length = 1/12 miles

width = 3/8 miles

 a = l × wa = 1/12 × 3/8Area = 3/96 square miles Perimeter = 2(l + w)= 2(1/12 + 3/8)= 2(2/24 + 9/24)= 2(11/24)= 22/24 milesperimeter = 11/12

Problem 4 :

The area for the dance floor is 45 square feet, and one side is 8 feet. What is the length of the other side ?

Solution :

Dance floor area = 45 square feet

Width = 8 feet

To find the length of the other side :

a = l × w

45 = l × 8

45/8 = l

5.625 = l

So, the length of the other side is 5.625.

Problem 5 :

Margo wants new carpet and a new wallpaper border for her bedroom. The room is 5.4 meters long and 4 7/8 meters wide.

About how many square meters of carpet will she need ?

About how many meters of wallpaper border will she need ?

Solution :

Length of the room = 5.4 meters

width = 4 7/8 meters

a = l × w

a = 5.4 × 4 7/8

= 5.4 × 39/8

= 54/10  × 39/8

= 27/5 × 39/8

= 1053/40

= 26.325

She will need 26.325 square meters of carpet.

Problem 6 :

Tomas has a garden with a length of 2.45 meters and a width of 5/8 meter. Use benchmarks to estimate the area and perimeter of the garden.

Solution :

length = 2.45 meters

width = 5/8 meter.

 area = l × w= 2.45 × 5/8= 12.25/8area = 1.53 square meter Perimeter = 2(l + w)= 2(2.45 + 5/8)= 4.9 + 10/8= (39.2 + 10)/8= 49.2/8= 6.15

Area of the garden is 1.53 square meter.

Perimeter of the garden is 6.15 meter.

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