Let a, b and c be the sides of the triangle.
Where a and b are the lengths of the two shorter sides and c be the length of the longest side.
State if the three side lengths form an acute, obtuse, or right triangle.
Problem 1 :
5, 12, 13
Solution:
Let a = 5, b = 12 and c = 13
c2 ? a2 + b2
13² ? 5² + 12²
169 ? 25 + 144
169 = 169
Because c2 is equal to a2 + b2, the triangle is right triangle.
Problem 2 :
4, 12, 13
Solution:
Let a = 4, b = 12 and c = 13
c2 ? a2 + b2
13² ? 4² + 12²
169 ? 16 + 144
169 > 160
Because c2 is greater than a2 + b2, the triangle is obtuse triangle.
Problem 3 :
9, 12, 15
Solution:
Let a = 9, b = 12 and c = 15
c2 ? a2 + b2
152 ? 92 + 122
225 ? 81 + 144
225 = 225
Because c2 is equal to a2 + b2, the triangle is right triangle.
Problem 4 :
3, 4, 5
Solution:
Let a = 3, b = 4 and c = 5
c2 ? a2 + b2
52 ? 32 + 42
25 ? 9 + 16
25 = 25
Because c2 is equal to a2 + b2, the triangle is right triangle.
Problem 5 :
9, 2√22, 13
Solution:
Let a = 9, b = 2√22 and c = 13
c2 ? a2 + b2
132 ? 92 + (2√22)2
169 ? 81 + 88
169 = 169
Because c2 is equal to a2 + b2, the triangle is right triangle.
Problem 6 :
√7, √11, 4
Solution:
Let a = √7, b = √11 and c = 4
c2 ? a2 + b2
42 ? √72 +√112
16 ? 7 + 11
16 < 18
Because c2 is less than a2 + b2, the triangle is acute triangle.
Problem 7 :
14, 5√7, 16
Solution:
Let a = 14, b = 5√7 and c = 16
c2 ? a2 + b2
162 ? 142 + (5√7)2
256 ? 196 + 175
256 < 371
Because c2 is less than a2 + b2, the triangle is acute triangle.
Problem 8 :
√11, √10, √21
Solution:
Let a = √11, b = √10 and c = √21
c2 ? a2 + b2
√212 ? √112 + √102
21 ? 11 + 10
21 = 21
Because c2 is equal to a2 + b2, the triangle is right triangle.
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