CALCULATING THE MEAN FROM A FREQUENCY TABLE

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

Work out the mean for each of these frequency tables, you may not use calculator.

Problem 1 :

Solution :

From the table, we understand that,

  • at the age of 5 we have 2 people
  • at the age of 6 we have 2 people
  • at the age of 7 we have 5 people
  • at the age of 8 we have 1 people

To find the total number of people, we will add 2, 2, 5 and 1.

Mean = 5(2)+6(2)+7(5)+8(1)2+2+5+1Mean = 10+12+35+810= 6510Mean = 6.5

Problem 2 :

Solution :

From the table, we understand that,

  • 1 person is having no phone (0 phones)
  • 3 persons is having 1phone.
  • 2 persons is having 2 phones.
  • No person is having 3 phones.
  • 4 persons is having 4 phones.
  • No person is having 5 phones.
Mean = 0(1)+1(3)+2(2)+3(0)+4(4)+5(0)1+3+2+0+4+0Mean = 0+3+4+0+16+010= 2310Mean=2.3

Problem 3 :

Solution :

Mean = 0(13)+1(28)+2(50)+3(9)13+28+50+9Mean = 0+28+100+27200= 155200= 0.775

Problem 4 :

Solution :

Mean = 0(34)+2(275)+3(512)+4(179)34+275+512+179Mean = 0+550+1536+7161000= 28021000= 2.802

Problem 5 :

Solution :

Mean = 3(1)+4(9)+5(7)+6(2)+7(1)1+9+7+2+1Mean = 3+36+35+12+720= 9320= 4.65

Problem 6 :

The tale below shows the data on the heights in cm of 51 children.

Class interval

140 ≤ h < 150

150 ≤ h < 160

160 ≤ h < 170

170 ≤ h < 180

Frequency

6

16

21

8

a) Estimate the mean

b) Estimate the median height

c) Find the modal class

Solution :

a) Calculating the mean :

Class interval

140 ≤ h < 150

150 ≤ h < 160

160 ≤ h < 170

170 ≤ h < 180

Midpoint

145

155

165

175

Frequency

6

16

21

8

M x F

870

2480

3465

1400

ΣMF = 870 + 2480 + 3465 + 1400

= 8215

ΣF = 6 + 16 + 21 + 8

= 51

Mean = ΣMF/ΣF

= 8215 / 51

= 161

b) Finding median :

ΣF = 51

Median value = 51/2

= 25.5

26th value will be the median.

26th value lies in the interval 160 ≤ h < 170, in this interval 4th value will be the median.

= 160 + (4/21) x 10

= 160 + (40/21)

= 160 + 1.9

= 161.9

Approximately 162 is the median.

c) Finding mode :

The high frequency is in the interval 160 ≤ h < 170 and this is the modal class.

Problem 6 :

The age of children in a primary school were recorded in the table below.

Number of days off sick

1 - 5

6 - 10

11 - 15

16 - 20

21 - 25

Frequency

12

11

10

4

3

a) Estimate the mean

b) Estimate the median

c) Estimate the modal class

Solution :

a) Calculating mean :

Class interval

1 - 5

6 - 10

11 - 15

16 - 20

21 - 25


1.5 to 4.5

5.5 to 9.5

11.5 to 14.5

16.5 to 19.5

21.5 to 25.5

Midpoint

3

8

13

18

23

Frequency

12

11

10

4

3

M x F

36

88

130

72

69

ΣMF = 36 + 88 + 130 + 72 + 69

= 395

ΣF = 12 + 11 + 10 + 4 + 3

= 40

Mean = ΣMF/ΣF

= 395 / 40

= 9.875

b) Finding median :

ΣF = 40

Median value = 40/2

= 20

20th value will be the median.

20th value lies in the interval 6 to 10, in this interval we have 11 values 

= 5.5 + (8.5/11) x 3

= 5.5 + 0.77 x 3

= 5.5 + 2.31

= 7.81

7.81 is the median.

c) Finding mode :

Highest frequency is in the interval 6 - 10, then this is the modal class.

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

Recent Articles

  1. Finding Range of Values Inequality Problems

    May 21, 24 08:51 PM

    Finding Range of Values Inequality Problems

    Read More

  2. Solving Two Step Inequality Word Problems

    May 21, 24 08:51 AM

    Solving Two Step Inequality Word Problems

    Read More

  3. Exponential Function Context and Data Modeling

    May 20, 24 10:45 PM

    Exponential Function Context and Data Modeling

    Read More