# BODMAS PRACTICE QUESTIONS

The simple rules to remember the BODMAS is given below.

• First, simplify operations within Brackets. ( ), { }, [ ]
• Second, evaluate the exponential form. 22
• Third, do the division and multiplication one by one from left to right. ÷ and ×
• Finally, do the addition and subtraction one by one from left to right. + and -

Note :

• If an expression has more than one set of brackets, do the innermost bracket first.
• If there is a division sign between two fractions, multiply by the reciprocal of the divisor fraction.

Question 1 :

Simplify 25 - [20 - {10 - (7-5-3)}]

Solution :

 = 25 - [20 - {10 - (7-5-3)}]= 25 - [20 - {10 + 1}]= 25 - [20 - 11]= 25 - 9= 16 Inner Bracket ( )Inner Bracket { }Bracket [ ]Subtraction

Question 2 :

Find out the answer for 100 - 3[20 + {50 - 40}]

Solution :

 = 100 - 3[20 + {50 - 40}]= 100 - 3[20 + 10]= 100 - 3 × 30= 100 - 90= 10 Inner Bracket { }Bracket [ ]MultiplicationSubtraction

Question 3 :

7 + (8 - 3 × 2)

Solution :

 = 7 + (8 - 3 × 2)= 7 + (8 - 6)= 7 + 2= 9 Bracket,  MultiplicationBracket,  SubtractionAddition

Question 4 :

What would be the answer for 50 - [20 + {30 - (20 - 5)}]

Solution :

 = 50 - [20 + {30 - (20 - 5)}]= 50 - [20 + {30 - 15}]= 50 - [20 + 15]= 50 - 35= 15 Inner Bracket ( )Inner Bracket { }Bracket [ ]Addition

Question 5 :

Find the value of 150 - [10 + {3 - (20 - 5)}]

Solution :

 = 150 - [10 + {3 - (20 - 5)}]= 150 - [10 + {3 - 15}]= 150 - [10 - 12]= 150 + 2= 152 Inner Bracket ( )Inner Bracket { }Bracket [ ]Addition

Question 6 :

Simplify 1 ÷ 3/7 × (6 + 8 × 3 - 2) + [1/5 ÷ 7/25 - {3/7 + 8/14}]

Solution :

Step 1 :

Find the value of ÷ 3/7 × (6 + 8 × 3 - 2).

 = 1 ÷ 3/7 × (6 + 8 × 3 - 2)= 1 ÷ 3/7 × (6 + 24 - 2)= 1 ÷ 3/7 × (30 - 2)= 1 × 7/3 × 28= 196/3 Bracket, MultiplicationBracket, AdditionBracket, SubtractionChange ÷ into ×

The value of 1 ÷ 3/7 × (6 + 8 × 3 - 1) = 196/3 ----(1)

Step 2 :

Find the value of [1/5 ÷ 7/25 - {3/7 + 8/14}]

[1/5 ÷ 7/25 - {3/7 + 8/14}]

The LCM of 7, 14 is 14

[1/5 ÷ 7/25 - {3/7 × 2/2 + 8/14}]

= [1/5 ÷ 7/25 - {6/14 + 8/14}

[1/5 ÷ 7/25 - {14/14}]

[1/5 ÷ 7/25 - 1]

= [1/5 × 25/7 - 1]

= [5/7 - 1]

= -2/7

The value of [1/5 ÷ 7/25 - {3/7 + 8/14}] = -2/7 ----(2)

Add (1) + (2), we get

= (196/3) + (-2/7)

= (196/3) - (2/7)

By using cross multiplication,

= (1372 - 6)/21

= (1366)/21

= 65.04

Question 7 :

Using the rule of BODMAS, determine the answer of

18 ÷ 10 - 4 + 32 ÷ (4 + 10 ÷ 2 - 1)

Solution :

 = 18 ÷ 10 - 4 + 32 ÷ (4 + 10 ÷ 2 - 1)= 18 ÷ 10 - 4 + 32 ÷  (4 + 5 - 1)= 18 ÷ 10 - 4 + 32 ÷ (9 - 1)= 18 ÷ 10 - 4 + 32 ÷ 8= 1.8 - 4 + 4= 1.8 Bracket, Division Bracket, Addition( ), SubtractionDivisionAddition

Question 8 :

10 - [6 - {7 - (6 - 8 - 5)}]

Solution :

 = 10 - [6 - {7 - (6 - 8 - 5)}]= 10 - [6 - {7 + 7}]= 10 - [6 - 14]= 10 + 818 Inner Bracket ( )Inner Bracket { }Inner Bracket [ ]Addition

Question 9 :

What will the answer of this question

× 1/4 ÷ 3/7 + [45/24 - 2/3 + 5/6 × 2/5]

Solution :

= 5 × 1/4 ÷ 3/7 + [45/24 - 2/3 + 5/6 × 2/5]

5 × 1/4 ÷ 3/7 +  [45/24 - 2/3 + 1/3]

5 × 1/4 ÷ 3/7 +  [45/24 - 1/3]

The LCM of 24, 3 is 24

5 × 1/4 ÷ 3/7 +  [45/24 - 1/3 × 8/8]

5 × 1/4 ÷ 3/7 +  [45/24 - 8/24]

× 1/4 ÷ 3/7 + 37/24

Changing ÷ into ×.

× 1/4 × 7/3 + 37/24

= 35/12 + 37/24

The LCM of 12, 24 is 24

35/12 × 2/2 + 37/24

= 70/24 + 37/24

= 107/24

= 4.46

Question 10 :

1800 ÷ 10 {(12 - 6) + (24 - 12)}

Solution :

 = 1800 ÷ 10{(12 - 6) + (24 - 12)}= 1800 ÷ 10 {6 + 12}= 1800 ÷ 10 × 18= 180 × 18= 3240 Inner Brackets ( )Inner Bracket { }DivisionMultiplication

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