Problem 1 :
Find the area of a triangle whose vertices are (3, 0), (7, 0) and (8, 4).
Problem 2 :
The area of a triangle whose vertices are (5, 0), (8, 0) and (8, 4) (in sq.units) is
A) 20 B) 12 C) 6
Problem 3 :
The area of a triangle is 5 sq units. Two of its vertices are (2, 1) and (3, -2). If the third vertex is (7/2, y), find the value of y.
Problem 4 :
Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.
Problem 5 :
Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are A(2, 1), B(4, 3) and C(2, 5).
Problem 6 :
For what type of k, (k > 0), is the area of the triangle with vertices (-2, 5), (k, -4) and (2k + 1, 10) to 53 sq. units?
1) 20 square units.
2) 6 square units.
3) y = 13/2
4) k = 3 and k = -9/2
5) 1 square unit
6) k = 3
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM