# AREA OF A SHAPE ON A GRID

Find the area of each triangle.

Problem 1 : Solution :

Base = 7 units

Height = 4 units

Area of triangle = 1/2 × b × h

= 1/2 × 7 × 4

= 14 units²

So, the area of triangle is 14 units².

Problem 2 : Solution :

Base = 6 units

Height = 5 units

Area of triangle = 1/2 × b × h

= 1/2 × 6 × 5

= 15 units²

So, the area of triangle is 15 units².

Problem 3 : Solution :

Base = 11 units

Height = 3 units

Area of triangle = 1/2 × b × h

= 1/2 × 11 × 3

= 16.5 units²

So, the area of triangle is 16.5 units².

Problem 4 : Solution :

By drawing the vertical line, we divide the shape into two rectangles. Solution :

Measures of rectangle in the left :

length = 3, width = 4

Area of rectangle = 3 x 4 ==> 12 cm---(1)

Measures of rectangle in the right :

length = 2, width = 6

Area of rectangle = 2 x 6 ==> 12 cm2 ---(2)

(1) + (2)

= 12 + 12

= 24 cm2

Find the area of each parallelogram.

Problem 5 : Solution :

Base = 4 units

Height = 3 units

Area of parallelogram = base × height

= 4 × 3

= 12 units²

So, the area of parallelogram is 12 units².

Problem 6 : Solution :

Base = 6 units

Height = 3 units

Area of parallelogram = base × height

= 6 × 3

= 18 units²

So, the area of parallelogram is 18 units².

Problem 7 : Solution :

Base = 7 units

Height = 5 units

Area of parallelogram = base × height

= 7 × 5

= 35 units²

So, the area of parallelogram is 35 units².

Problem 8 : Solution :

Area of a circle = πr2

= 22/7 × 22

= 22/7 × 4

= 12.57 units2

Problem 9 : Solution :

Area of a circle = πr2

= 22/7 × 42

= 22/7 × 16

= 50.28 units2

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