What is the Area of Rectangle ?
The Area of Rectangle is the region occupied by a rectangle within four sides or boundaries.
The formula for the Area of a Rectangle,
Area of a Rectangle = Length × width
What is the Perimeter of Rectangle ?
The perimeter of a Rectangle is the total distance covered by its boundaries or the sides.
The formula for the Perimeter of a Rectangle is defined as the sum of all the sides of a rectangle.
Perimeter = 2(a + b)
(Where a is the length of the rectangle, and b is the breadth of the rectangle)
Problem 1 :
The area of a rectangle is 42 cm^{2}. If its length is 7cm, What is its width ?
Solution :
Given, Area = 42 cm^{2}, Length = 7 cm, and width = ?
Area of a rectangle = Length × width
42 = 7 × width
(42)/7 = width
width = 6 cm
Problem 2 :
The perimeter of a square is 32 meters. Find the length of one side of the square.
Solution :
Given, Perimeter = 32 meters.
Perimeter of a square = 4a
(Here a is the length of one side of the square.)
32 = 4a
32/4 = a
a = 8
Problem 3 :
The Length of a rectangle is 13 cm. what is the width if the area is 65 cm^{2 }?
Solution :
Given, Area = 65 cm^{2}, Length = 13 cm, and width = ?
Area of a rectangle = Length × width
65 = 13 × width
(65)/13 = width
width = 5 cm
Problem 4 :
The area of a square is 81 mm^{2}. What is the length of each side?
Solution :
Given, Area = 81 mm^{2}.
Area of a square = a^{2}
(Here a is the length of each side of the square).
81 = a^{2}
a = √81
a = 9 mm
Problem 5 :
The area of a rectangle is 40 cm^{2}. If its length is 10 cm, what is its width?
Solution :
Given, Area = 40 cm^{2}, length = 10 cm, and width = ?
Area of a rectangle = Length × width
40 = 10 × width
(40)/10 = width
width = 4 cm
Problem 6 :
The perimeter of a rectangle is 200 cm. The rectangle is 3 times longer than wide. What are the length and width of this rectangle ?
Solution :
Given, Perimeter = 200 cm.
Let the width be x.
Then the length is 3x.
Perimeter of a rectangle = 2(length + width)
200 = 2(3x + x)
200 = 6x + 2x
200 = 8x
200/8 = x
x = 25 cm.
Now,
Length = 3(x)
= 3(25)
Length = 75 cm
Width = x
Width = 25 cm
Problem 7 :
The Length of a rectangle is 10 cm. what is the width if the area is 60 cm^{2 }?
Solution :
Given, Area = 60 cm^{2}, Length = 10 cm, and width = ?
Area of a rectangle = Length × width
60 = 10 × width
(60)/10 = width
width = 6 cm
Problem 8 :
The area of a rectangle is 48 cm^{2}. If its length is 12 cm, what is its width ?
Solution :
Given, Area = 48 cm^{2}, Length = 12 cm, and width = ?
Area of a rectangle = Length × width
48 = 12 × width
(48)/12 = width
width = 4 cm
Problem 9 :
The area of a rectangle is 27 cm^{2}. If its length is 9 cm, what is its width ?
Solution :
Given, Area = 27 cm^{2}, Length = 9 cm, and width = ?
Area of a rectangle = Length × width
27 = 9 × width
(27)/9 = width
width = 3 cm
Problem 10 :
Norman is a sunflower farmer. He uses a plot of land that is 3 km by 4.3 km. How much land does he use for his sunflowers?
Solution :
Norman uses the land which has dimensions of 3 km by 4.3 km.
The land is in a rectangular shape.
We find the area of a rectangular land.
Area of a rectangular land = Length × width
Length = 3 km, width = 4.3 km
Area = 3 × 4.3
Area = 12.9 km^{2}
He used 12.9 km^{2} of land for sunflowers.
Problem 11 :
Before soccer practice Allyson jogs around the field that measures 100 yards by 65 yards twice. How far will she jog ?
Solution :
Given, field that measures 100 yards by 65 yards.
we find the perimeter of the field.
Perimeter of a rectangle = 2(length + width)
Length = 100 yards, width = 65 yards
Perimeter = 2(100 + 65)
= 2(165)
Perimeter = 330 yards.
she runs twice,
= 2(330)
= 660 yards.
She will jog 660 yards.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM