7TH GRADE MATH STAAR PROBLEMS

Problem 1 :

The length of a ruler is 12 inches. There are approximately 25.4 millimeters in 1 inch.

Which measurement is closest to the length of the ruler in millimeters?

A. 3,048 mm     B. 30.48 mm     C. 304.8 mm    D. 3.048 mm

Solution:

1 inch = 25.4 mm

Length of a ruler 12 inches = 12 × 25.4

= 304.8 mm

Hence, the length of the ruler is 304.8 mm.

So, option (C) is corrrect.

Problem 2 :

The table shows the numbers of bags of different flavors of potato chips on a store shelf. A customer will randomly select one bag of potato chips from the shelf.

potato-chips-table

Which statement about the flavor of the potato chips chosen is best supported by the information in the table?

A. The flavor is least likely to be plain.

B. The flavor is twice as likely to be jalapeno as ranch.

C. The flavor is equally likely to be plain, jalapeno, ranch, or cheese.

D. The flavor is more than twice as likely to be cheese as it is to be ranch.

Solution:

A. False (The flavor is least likely to be ranch).

B.

P(Jalapeno)=1858P(ranch)=85818582×858

C. False

D.

P(cheese)=2058P(ranch)=8582058>2×858

True

So, option (D) is correct.

Problem 3 :

Nicole had a collection of 60 stuffed animals. She gave away 5 stuffed animals per month until all her stuffed animals were gone.

Which graph best represents this situation?

stuffed-animal-collection1
stuffed-animal-collection2

Solution :

Considering option A, it starts with 60 animals, it is a falling line and end at (12, 0). It means, after 12 months the number of stuffed animals will become 0.

So, option A is correct.

Problem 4 :

This figure is composed of a parallelogram and a trapezoid.

staar-test-math-q4

What is the area of the figure in square centimeters?

A. 1,056 cm2     B. 1,360 cm2      C. 944 cm2    D. 528 cm2

Solution:

Area = Area of parallelogram + Area of trapezoid

Area of parallelogram = l × b

= 16 × 26 = 416 cm2

Area of trapezoid=(a+b)2×hwhere a=26 cm, b = 40 cm, h=16 cmArea of trapezoid=(26+40)2×16=66×8=528 cm2

So, option (C) is correct. 

Problem 5 :

Triangle QRS and its dimensions are shown.

staar-test-math-q5.png

Which measurements in centimeters represent the dimensions of a triangle that is similar to triangle QRS?

A. 8 cm, 14 cm, 17 cm       B. 10 cm, 20 cm, 25 cm

C. 4 cm, 10 cm, 13 cm       D. 12 cm, 24 cm, 36 cm

Solution:

10a=20b=25c106=2012=251553=53=53

So, option (B) is correct.

Problem 6 :

Which equation is true when x = 4?

A. 3x + 4 = 8        B. 5x - 2 = 18

C. 2x + 8 = 40      D. 4x + 4 = 12

Solution:

5x - 2 = 18

Substitute x = 4 in equation,

 5(4) - 2 = 18

 20 - 2 = 18

 18 = 18

So, option (B) is correct.

Problem 7 :

The dimensions of a rectangular pyramid are shown in the diagram.

staar-test-math-q7

What is the volume of the rectangular pyramid in cubic millimeters?

A. 15 mm3   B. 120 mm3    C. 60 mm3    D. 40 mm3

Solution:

Volume of rectangular pyramid V=l×b×h3Here l = 4 mm, w=5 mm and h=6mmV=4×5×63V=40 mm3

So, option (D) is correct.

Problem 8 :

Imani compared the number of fluid ounces per bottle of sunscreen to the cost of four different brands of sunscreen. The information she gathered is shown in the table.

staar-test-math-q8

Based on the data in the table, which brand of sunscreen has the greatest cost per fluid ounce?

A. Brand W       B. Brand X    C. Brand Y       D. Brand Z

Solution:

Brand=costfluid ouncesBrand W=1220=0.6Brand X=11.2515=0.75Brand Y=6.5010=0.65Brand Z=2.505=0.5

Therefore, brand X has the greatest cost per fluid ounces, at 0.75 dollars per fluid ounce.

So, option (B) is correct.

Problem 9 :

Chad will have new carpet put on the rectangular floors of two rooms in his house. One floor is 12 1/2 feet long, and the other floor is 15 3/4 feet long. Each floor has a width of 10 feet.

What is the total area in square feet of the new carpet?

A. 125 ft2    B. 157.5 ft2    C. 282.5 ft2    D. 96.5 ft2

Solution:

Area of rectangle = length × width

The area of one floor will be,

A1=1212×10=252×10A1=125 ft2

The area of another floor will be,

A2=1534×10=634×10A2=157.5 ft2

Total area A = A1 + A2

A = 125 + 157.5

A = 282.5 ft²

Hence, the total area is 282.5 ft².

So, option (C) is correct.

Problem 10 :

A scientist measured the weights of squirrels in two populations. The dot plots display data from each population.

staar-test-math-q10.png

Which statement is best supported by the information in the dot plots?

A. The two populations have different mode weights.

B. The two populations have different median weights.

C. The data for the two populations have different skews.

D. The data for the two populations have different ranges.

Solution:

A) Modes are same

B) Median = 15

D) Range for population 1 :

18 - 12 = 6

Range for population 2 :

19 - 11 = 8

Both are having different ranges. So, option D is correct.

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