Problem 1 :
Find the value of 28 × 7000
(1) 196 (3) 19600 
(2) 1960 (4) 196000 
Solution :
When multiplying integer by the numeral which ends with zeroes, we can leave the zeroes and multiply the integers is enough and add the zeroes at the end of the result.
28 x 7 = 196
Number of zeroes we have at the end is 3. So, write the three zeroes at the end of the result.
28 x 700 = 196000
Hence, option (4) is correct.
Problem 2 :
Find the value of 300 + 100 ÷ 5  12 × 5.
(1) 20 (3) 340 
(2) 260 (4) 1540 
Solution :
= 300 + 20  60
= 320  60
= 260
Hence, option (2) is correct.
Problem 3 :
Express 3 5/8 as a decimal.
(1) 3.58 (3) 3.125 
(2) 3.85 (4) 3.625 
Solution :
3 5/8 = 3 + 5/8
= 3 + (5/8) x (125/125)
= 3 + 625/1000
= 3 + 0.625
= 3.625
So, option 4 is correct.
Problem 4 :
Which digit in 23.479 is in the tenths place ?
(1) 7 (3) 9 
(2) 2 (4) 4 
Solution :
Given, 23.479
The digits in tenths place is 4.
Hence, option (4) is correct.
Problem 5 :
Part of a scale is shown below. What is the most likely value of the reading at A ?
(1) 3.6 (3) 3.06 
(2) 3.4 (4) 3.04 
Solution :
Number of spaces in between 2.9 and 3 is 4
0.1/4 = 0.025
In between 3 and 3.1 will be 3.025,
Part of scale measure is 3.025, 3.05, 3.075 and 3.1
So, the value of A is 3.06.
Hence, option (3) is correct.
wProblem 6 :
Express 8.07 l in litres and millilitres.
(1) 8 l 7 ml (3) 80 l 7 ml 
(2) 8 l 70 ml (4) 80 l 70 ml 
Solution :
8.07 l
= 8 l + 0.07 l
= 8 l + 70/1000 l
= 8 l + 70 ml
= 8 l 70 ml
Hence, option (2) is correct.
Problem 7 :
Shaun had 11 kg of rice. He had 6 times as much rice as Pete. How much rice did Pete have at first ?


Solution :
Shaun had 11 kg of rice. He had 6 times as much rice as Pete. How much rice did Pete have at first ?
Quantity of rice Shaun has = 11 kg
6 x Quantity of rice Pete has = 11
Quantity of rice Pete has = 11/6
Expressing it as mixed fraction, we get
= 1 5/6
Problem 8 :
The table below shows the number of goals scored by the soccer teams.
How many goals did all the teams score altogether ?
(1) 10 (3) 40 
(2) 20 (4) 44 
Solution :
Total number of goals
= (4 × 0) + (3 × 1) + (5 × 2) + (5 × 3) + (3 × 4)
= 0 + 3 + 10 + 15 + 12
= 40
Hence, all the teams score the goals is 40.
So, option (3) is correct.
Problem 9 :
The figure below shows a trapezium. Which one of the following is correct ?
(1) ∠a = ∠c (3) ∠c + ∠d = 180^{º} 
(2) ∠b = ∠c (4) ∠a + ∠d = 180^{º} 
Solution :
In every trapezium, a pair of opposite sides will be parallel and other pairs will not be parallel.
Since the pair of sides are parallel, angle a and d can be considered as cointerior angles and they add up to 180 degree.
∠c + ∠d = 180º
Hence, option (3) is correct.
Problem 10 :
There were 96 vehicles in the carpark. 72 were cars and the rest were motorcycles. What was the ratio of the number of cars to the number of motorcycles ?
(1) 1 : 3 (3) 3 : 1 
(2) 1 : 4 (4) 3 : 4 
Solution :
Number of vehicles = 96
Number of cars = 72
The ratio of the number of cars to the number of motorcycles is
= 72 ÷ (96  72)
= 72 ÷ 24
= 3 : 1
Hence, option (3) is correct.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM