# 5TH GRADE MATH WORD PROBLEMS MIXED OPERATIONS

Problem 1 :

Find the value of 28 × 7000

 (1) 196(3) 19600 (2) 1960(4) 196000

Solution :

When multiplying integer by the numeral which ends with zeroes, we can leave the zeroes and multiply the integers is enough and add the zeroes at the end of the result.

28 x 7 = 196

Number of zeroes we have at the end is 3. So, write the three zeroes at the end of the result.

28 x 700 = 196000

Hence, option (4) is correct.

Problem 2 :

Find the value of 300 + 100 ÷ 5  - 12 × 5.

 (1) 20(3) 340 (2)  260(4) 1540

Solution :

= 300 + 20 - 60

= 320 - 60

= 260

Hence, option (2) is correct.

Problem 3 :

Express 3 5/8 as a decimal.

 (1) 3.58(3) 3.125 (2) 3.85(4) 3.625

Solution :

3  5/8 = 3 + 5/8

= 3 + (5/8) x (125/125)

= 3 + 625/1000

= 3 + 0.625

= 3.625

So, option 4 is correct.

Problem 4 :

Which digit in 23.479 is in the tenths place ?

 (1) 7(3) 9 (2) 2(4) 4

Solution :

Given, 23.479

The digits in tenths place is 4.

Hence, option (4) is correct.

Problem 5 :

Part of a scale is shown below. What is the most likely value of the reading at A ?

 (1) 3.6(3) 3.06 (2) 3.4(4) 3.04

Solution :

Number of spaces in between 2.9 and 3 is 4

0.1/4 = 0.025

In between 3 and 3.1 will be 3.025,

Part of scale measure is 3.025, 3.05, 3.075 and 3.1

So, the value of A is 3.06.

Hence, option (3) is correct.

wProblem 6 :

Express 8.07 l in litres and millilitres.

 (1) 8 l 7 ml(3) 80 l 7 ml (2) 8 l 70 ml(4) 80 l 70 ml

Solution :

8.07 l

= 8 l + 0.07 l

= 8 l + 70/1000 l

= 8 l + 70 ml

= 8 l 70 ml

Hence, option (2) is correct.

Problem 7 :

Shaun had 11 kg of rice. He had 6 times as much rice as Pete. How much rice did Pete have at first ?

 (1) 611 kg (3) 156 kg (2) 511 kg (4) 215 kg

Solution :

Shaun had 11 kg of rice. He had 6 times as much rice as Pete. How much rice did Pete have at first ?

Quantity of rice Shaun has = 11 kg

6 x Quantity of rice Pete has = 11

Quantity of rice Pete has = 11/6

Expressing it as mixed fraction, we get

= 1  5/6

Problem 8 :

The table below shows the number of goals scored by the soccer teams.

How many goals did all the teams score altogether ?

 (1) 10(3) 40 (2) 20(4) 44

Solution :

Total number of goals

= (4 × 0) + (3 × 1) + (5 × 2) + (5 × 3) + (3 × 4)

= 0 + 3 + 10 + 15 + 12

= 40

Hence, all the teams score the goals is 40.

So, option (3) is correct.

Problem 9 :

The figure below shows a trapezium. Which one of the following is correct ?

 (1) ∠a = ∠c(3) ∠c + ∠d = 180º (2) ∠b = ∠c(4) ∠a + ∠d = 180º

Solution :

In every trapezium, a pair of opposite sides will be parallel and other pairs will not be parallel.

Since the pair of sides are parallel, angle a and d can be considered as co-interior angles and they add up to 180 degree.

∠c + ∠d = 180º

Hence, option (3) is correct.

Problem 10 :

There were 96 vehicles in the carpark. 72 were cars and the rest were motorcycles. What was the ratio of the number of cars to the number of motorcycles ?

 (1) 1 : 3(3) 3 : 1 (2) 1 : 4(4) 3 : 4

Solution :

Number of vehicles = 96

Number of cars = 72

The ratio of the number of cars to the number of motorcycles is

= 72 ÷ (96 - 72)

= 72 ÷ 24

= 3 : 1

Hence, option (3) is correct.

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